Workers at a private business was given a grade (A, B, C) based on their yearly performance. The data was recorded along with the department they belong.  The results obtained using MINITAB are shown below:     Expected counts are printed below observed counts                                     A                     B                     C                     Total Accounting                 12                    8                      7                      *                                     (12.960)           (7.830)             (6.210) Sales                            17                    10                    8                      35                                     (16.800)           (10.150)           (8.050) Marketing                  19                    11                    8                      38                                     (18.240)           (**)                  (8.740) Total                           48                    29                    23                    100   Chi-sq =          0.0711 + 0.0037 + 0.1005 +                         0.0024 + 0.0022 + 0.0003 +                         0.0317 + 0.000 + *** = 0.2746 DF = ??, p-value =???   a) Carefully define the null and alternative hypotheses of the ?2 test of the above table. b) Find the missing values ‘*’, ‘**’, ‘***’ ??,??? c) What is the conclusion of this test? Give reasons for your answer. Could the p-value be calculated using another way like chi square table instead of excel format?

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Workers at a private business was given a grade (A, B, C) based on their yearly performance. The data was recorded along with the department they belong.  The results obtained using MINITAB are shown below: 

 

 Expected counts are printed below observed counts

                                    A                     B                     C                     Total

Accounting                 12                    8                      7                      *

                                    (12.960)           (7.830)             (6.210)

Sales                            17                    10                    8                      35

                                    (16.800)           (10.150)           (8.050)

Marketing                  19                    11                    8                      38

                                    (18.240)           (**)                  (8.740)

Total                           48                    29                    23                    100

 

Chi-sq =          0.0711 + 0.0037 + 0.1005 +

                        0.0024 + 0.0022 + 0.0003 +

                        0.0317 + 0.000 + *** = 0.2746

DF = ??, p-value =???

 

  1. a) Carefully define the null and alternative hypotheses of the ?2 test of the above table.
  2. b) Find the missing values ‘*’, ‘**’, ‘***’ ??,???
  3. c) What is the conclusion of this test? Give reasons for your answer.

Could the p-value be calculated using another way like chi square table instead of excel format?

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