Calculate enthalpy changes for the following: a. 0.089 g of sulfur (rhombic) burns, forming SO₂(g) ( AƒH˚ for SO₂(g) = - 296.84 kJ/mol) Enthalpy change b. 0.28 mol of c. 2.20 g of d. = HgO(s) decomposes to Hg(l) and O2(g) ( AfH for HgO = -90.83 kJ/mol) Enthalpy change = NH3(g) is formed from N₂(g) and excess H₂(g) ( AfH for NH3 = -45.90 kJ/mol) Enthalpy change = kJ kJ kJ [Review Topics] 1.19 x 10-2 mol of carbon is oxidized to CO2(g) ( AfH for CO2 = -393.509 kJ/mol) Enthalpy change = kJ [References]

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Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Calculate enthalpy changes for the following:
a. 0.089 g of sulfur (rhombic) burns, forming
SO₂(g) (
▲ƒH˚ for
SO₂ (g) = - 296.84 kJ/mol)
Enthalpy change
b. 0.28 mol of
d.
=
HgO(s) decomposes to
Hg(l) and
O₂(g) (
c. 2.20 g of
Af HⓇ for
HgO = -90.83 kJ/mol)
Enthalpy change =
NH3(g) is formed from
N₂(g) and excess
H₂(g) (
Af HⓇ for
NH3 = -45.90 kJ/mol)
Enthalpy change
=
KJ
=
kJ
kJ
[Review Topics]
A
1.19 x 10-2 mol of carbon is oxidized to
CO2(g) (
AfH for
CO2 = -393.509 kJ/mol)
Enthalpy change
kJ
[References]
Transcribed Image Text:Calculate enthalpy changes for the following: a. 0.089 g of sulfur (rhombic) burns, forming SO₂(g) ( ▲ƒH˚ for SO₂ (g) = - 296.84 kJ/mol) Enthalpy change b. 0.28 mol of d. = HgO(s) decomposes to Hg(l) and O₂(g) ( c. 2.20 g of Af HⓇ for HgO = -90.83 kJ/mol) Enthalpy change = NH3(g) is formed from N₂(g) and excess H₂(g) ( Af HⓇ for NH3 = -45.90 kJ/mol) Enthalpy change = KJ = kJ kJ [Review Topics] A 1.19 x 10-2 mol of carbon is oxidized to CO2(g) ( AfH for CO2 = -393.509 kJ/mol) Enthalpy change kJ [References]
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