Calculate enthalpy changes for the following:a. 0.084 g of sulfur (rhombic) burns, formingSO2(g) (AfH forSO2(g) = 296.84 kJ/mol)==Enthalpy changeb. 0.23 mol ofd.c. 3.07 g ofHgO(s) decomposes toHg() andO2(g) (AfH forHgO -90.83 kJ/mol)Enthalpy change ==NH3(g) is formed fromN₂(g) and excessH₂(g) (AfH forNH3=-45.90 kJ/mol)Enthalpy change =kJkJkJ1.76 x 10-2 mol of carbon is oxidized toCO2(g) (AfH forCO2 = -393.509 kJ/mol)Enthalpy change[Review Topics]kJ

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Calculate enthalpy changes for the following: a. 0.084 g of sulfur (rhombic) burns, forming SO2(g) ( AfH for SO2(g) = 296.84 kJ/mol) - Enthalpy change = = b. 0.23 mol of HgO(s) decomposes to Hg(l) and O2(g) ( AfH for HgO = -90.83 kJ/mol) Enthalpy change = kJ kJ

Calculate enthalpy changes for the following: a. 0.084 g of sulfur (rhombic) burns, forming SO2(g) ( AfH for SO2(g) = 296.84 kJ/mol) - Enthalpy change = = b. 0.23 mol of HgO(s) decomposes to Hg(l) and O2(g) ( AfH for HgO = -90.83 kJ/mol) Enthalpy change = kJ kJ

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Question

100%

Calculate enthalpy changes for the following:
a. 0.084 g of sulfur (rhombic) burns, forming
SO2(g) (
AfH for
SO2(g) = 296.84 kJ/mol)
==
Enthalpy change
b. 0.23 mol of
d.
c. 3.07 g of
HgO(s) decomposes to
Hg() and
O2(g) (
AfH for
HgO -90.83 kJ/mol)
Enthalpy change =
=
NH3(g) is formed from
N₂(g) and excess
H₂(g) (
AfH for
NH3
=
-45.90 kJ/mol)
Enthalpy change =
kJ
kJ
kJ
1.76 x 10-2 mol of carbon is oxidized to
CO2(g) (
AfH for
CO2 = -393.509 kJ/mol)
Enthalpy change
[Review Topics]
kJ

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