Consider the following two reactions and write down the balanced chemical equations. Reaction 1: Formic acid (CH202, 1) reacts with oxygen to produce liquid water and carbon dioxide gas. The enthalpy change for this reaction is A,H=-255 kJ mol-1 (per mole of CH2O2). Reaction 2: The formation reaction for CO2(g). The enthalpy of formation for CO2(g) is AH= -394 k) mol-1 Given the data above, what is the enthalpy of reaction for: C(gr) + H,O(1) + 0,(g) → CH, O, (1) A,H = Number kJ mol-1

Principles of Modern Chemistry
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Author:David W. Oxtoby, H. Pat Gillis, Laurie J. Butler
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Chapter12: Thermodynamic Processes And Thermochemistry
Section: Chapter Questions
Problem 28P: For each of the following reactions, the enthalpy change given is that measured when the numbers of...
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Consider the following two reactions and write down the balanced chemical equations.
Reaction 1: Formic acid (CH202, ) reacts with oxygen to produce liquid water and carbon dioxide gas. The
enthalpy change for this reaction is A,H= -255 kJ mol-1 (per mole of CH202).
Reaction 2: The formation reaction for CO2(g). The enthalpy of formation for CO2(g) is
A:H= -394 k) mol-1
Given the data above, what is the enthalpy of reaction for:
C(gr) + H,O(1) +0,(g) → CH, O,(1)
A,H = Number
kJ mol-1
%3D
Transcribed Image Text:Consider the following two reactions and write down the balanced chemical equations. Reaction 1: Formic acid (CH202, ) reacts with oxygen to produce liquid water and carbon dioxide gas. The enthalpy change for this reaction is A,H= -255 kJ mol-1 (per mole of CH202). Reaction 2: The formation reaction for CO2(g). The enthalpy of formation for CO2(g) is A:H= -394 k) mol-1 Given the data above, what is the enthalpy of reaction for: C(gr) + H,O(1) +0,(g) → CH, O,(1) A,H = Number kJ mol-1 %3D
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