Calculate and report the standard error for the sampling distribution of (the difference between two means) given the following information: n2 500 19 %3D S2 n1 = 400 S1 = 15 %3D %3D
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- Archery. A champion archer can generally hit the bull’s-eye 80% of the time. Suppose she shoots 200 arrows during competition. Let pn represent the percentage ofbull’s-eyes she gets (the sample proportion).a) What are the mean and standard deviation of thesampling distribution model for pn?b) Is a Normal model appropriate here? Explain.c) Sketch the sampling model, using the 68–95–99.7 Rule.d) What’s the probability that she gets at least 85%bull’s-eyes?I need assistance with D and E Only. Given the sample data. x: 23, 17, 15, 32, 27 (a) Find the range. (Enter an exact number.) (b) Verify that Σx = 114 and Σx2 = 2,796. (For each answer, enter an exact number.)Σx = Σx2 = (c) Use the results of part (b) and appropriate computation formulas to compute the sample variance s2 and sample standard deviation s. (For each answer, enter a number. Round your answers to two decimal places.)s2 = s = (d) Use the defining formulas to compute the sample variance s2 and sample standard deviation s. (For each answer, enter a number. Round your answers to two decimal places.)s2 = s = (e) Suppose the given data comprise the entire population of all x values. Compute the population variance σ2 and population standard deviation σ. (For each answer, enter a number. Round your answers to two decimal places.)σ2 = σ =For the following sample, use the computational formula to calculate SS and then compute the sample variance and standard deviation. Scores: 1, 3, 1, 1
- Distribution of sample means e.A sampling distribution (dotplot) for the mean quiz score for a sample n = 30 of STAT101 students is shown below. It was constructed using random samples from population data. What does one dot in this dotplot represent?According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in…