Calculate and report the standard error for the sampling distribution of (the difference between two means) given the following information: n2 500 19 %3D S2 n1 = 400 S1 = 15 %3D %3D
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- 44Archery. A champion archer can generally hit the bull’s-eye 80% of the time. Suppose she shoots 200 arrows during competition. Let pn represent the percentage ofbull’s-eyes she gets (the sample proportion).a) What are the mean and standard deviation of thesampling distribution model for pn?b) Is a Normal model appropriate here? Explain.c) Sketch the sampling model, using the 68–95–99.7 Rule.d) What’s the probability that she gets at least 85%bull’s-eyes?prilame Performance Task: You are apart-time crew at a fast food chain. Suppose you serve a certain number of customers every hour. Assume the number of people you have served in 3 hours and let this be your population (choose three numbers only). Assume that samples of size n = 2 are randomly selected without replacement from the population. Find the population mean u and the mean ug of the sampling distribution of the means. nimets el eiTT olemeieq A A. Population: B. Population Mean: C. Means of Samples Drawn without Replacement from the Population (your choice of numbers) (Show solution) ot ort lo roirW Observation Sample Mean of the Sampling Distribution of the Sample Mean: (Show solution)
- The standard deviation of any sampling distribution is called a: A. Standard error B. Type- I error C. Non-sampling error D. Type II-errorI need assistance with D and E Only. Given the sample data. x: 23, 17, 15, 32, 27 (a) Find the range. (Enter an exact number.) (b) Verify that Σx = 114 and Σx2 = 2,796. (For each answer, enter an exact number.)Σx = Σx2 = (c) Use the results of part (b) and appropriate computation formulas to compute the sample variance s2 and sample standard deviation s. (For each answer, enter a number. Round your answers to two decimal places.)s2 = s = (d) Use the defining formulas to compute the sample variance s2 and sample standard deviation s. (For each answer, enter a number. Round your answers to two decimal places.)s2 = s = (e) Suppose the given data comprise the entire population of all x values. Compute the population variance σ2 and population standard deviation σ. (For each answer, enter a number. Round your answers to two decimal places.)σ2 = σ =For the following sample, use the computational formula to calculate SS and then compute the sample variance and standard deviation. Scores: 1, 3, 1, 1
- Q5) The following data represent the yield on 90 consecutive batches of ceramic substrate to which a metal coating has been applied by a vapor-deposition process. Find the sample mean, median, variance and coefficient of variation of the given data. 94.186.1 95.3 84.9 88.8 84.6 94.4 84.1 93.2 90.4 94.1 78.3 86.4 83.6 96.1 83.7 90.6 89.1 97.8 89.6 85.1 85.4 98.0 82.9 91.4 87.3 93.1 90.3 84.0 89.7 85.4 87.3 88.2 84.1 86.4 93.1 93.7 87.6 86.6 86,4 86.1 90.1 87.6 94.6 87.7 85.1 91.7 84.5 95.1 95.2 94.1 96.3 90.0 86.1 92.1 94.7 89.4 90,6 89.6 90.0 90.1 92.4 94.3 96,4 87.3 93.2 88.2 86,6 86.7 86,4 91.1 88.6 92.4 84.1 94.3 90.6 82.6 97.3 91.2 83.0 85.0 89.1 83.1 96.8 87.5 84.2 85.1 90.5 95.6 88.3Distribution of sample means e.3. In a sampling experiment s₁ = 3-6, s₂ = 2.0 and v₁ = 5, v₂ = 10. Is the difference between s₁ and s2 significant at the percent level?
- A sampling distribution (dotplot) for the mean quiz score for a sample n = 30 of STAT101 students is shown below. It was constructed using random samples from population data. What does one dot in this dotplot represent?According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in…According to a survey in a country, 38% of adults do not own a credit card. Suppose a simple random sample of 500 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. OA. Approximately normal because n ≤0.05N and np(1-p) 10 Determine the mean of the sampling distribution of p. H₂ = (Round to two decimal places as needed.)
