According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card? The probability is (Round to four decimal places as needed.)

According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below. (a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below. O A. Not normal because ns0.05N and np(1-p)<10 O B. Not normal because ns 0.05N and np(1-p)2 10 O C. Approximately normal because ns0.05N and np(1 -p)< 10 O D. Approximately normal because n<0.05N and np(1-p)2 10 Determine the mean of the sampling distribution of p. HA = (Round to two decimal places as needed.) Determine the standard deviation of the sampling distribution of p. OA = (Round to three decimal places as needed.) (b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card? The probability is (Round to four decimal places as needed.) (c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card? The probability is (Round to four decimal places as needed.)

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.

Question

According to a survey in a country, 24% of adults do not own a credit card. Suppose a simple random sample of 900 adults is obtained. Complete parts (a) through (d) below.
(a) Describe the sampling distribution of p, the sample proportion of adults who do not own a credit card. Choose the phrase that best describes the shape of the sampling distribution of p below.
O A. Not normal because ns0.05N and np(1-p)<10
O B. Not normal because ns 0.05N and np(1-p)2 10
O C. Approximately normal because ns0.05N and np(1 -p)< 10
O D. Approximately normal because n<0.05N and np(1-p)2 10
Determine the mean of the sampling distribution of p.
HA =
(Round to two decimal places as needed.)
Determine the standard deviation of the sampling distribution of p.
OA =
(Round to three decimal places as needed.)
(b) What is the probability that in a random sample of 900 adults, more than 27% do not own a credit card?
The probability is
(Round to four decimal places as needed.)
(c) What is the probability that in a random sample of 900 adults, between 22% and 27% do not own a credit card?
The probability is
(Round to four decimal places as needed.)

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