Calculate and plot the stress distribution with depth at a point 6.0 m from the corner (along the longest side) of a rectangularly loaded area 18 × 24 m with a uniform pressure of 175 kPa. Perform the calculation using the Boussinesq theoryand the 2:1 method. Comment on the results. When plotting stress distribution with depth, make sure the vertical axis (i.e. depth) increases downwards. Use z=0, 1, 5, 10, 15, 35, 50, and 100 m. Equations that may be helpful are attached.
Calculate and plot the stress distribution with depth at a point 6.0 m from the corner (along the longest side) of a rectangularly loaded area 18 × 24 m with a uniform pressure of 175 kPa. Perform the calculation using the Boussinesq theoryand the 2:1 method. Comment on the results. When plotting stress distribution with depth, make sure the vertical axis (i.e. depth) increases downwards. Use z=0, 1, 5, 10, 15, 35, 50, and 100 m. Equations that may be helpful are attached.
Chapter2: Loads On Structures
Section: Chapter Questions
Problem 1P
Related questions
Question
Calculate and plot the stress distribution with depth at a point 6.0 m from the corner (along the longest side) of a rectangularly loaded area 18 × 24 m with a uniform pressure of 175 kPa. Perform the calculation using the Boussinesq theoryand the 2:1 method. Comment on the results.
When plotting stress distribution with depth, make sure the vertical axis (i.e. depth) increases downwards. Use z=0, 1, 5, 10, 15, 35, 50, and 100 m. Equations that may be helpful are attached.
![►Line load P:
2P
z3
2
π (r² +2²)2
► Corner of a uniformly loaded rectangular area:
qo
mn
2 [√m² +² +1 (m²+1 +²41)
2T
2
2
mn
= qol with I=
0₂ =
O₂ =
z
1
+ tan-¹
1
= [√m²
+
2π /m² +n²+1 m² +1
2
2
2
mn
√m² +n² +1,
F1)
1
n²+1
+ tan-¹
mn
F
√m² + n²+1,
2
2
where: qo: surface stress; m = x/z; n = y/z; x and y: length and width of the
uniformly loaded area](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F40578013-3e17-4421-b4af-d1f1eb4da799%2F0b986a07-e93c-4006-82f8-f2c820dc8101%2Fn4f14uo_processed.jpeg&w=3840&q=75)
Transcribed Image Text:►Line load P:
2P
z3
2
π (r² +2²)2
► Corner of a uniformly loaded rectangular area:
qo
mn
2 [√m² +² +1 (m²+1 +²41)
2T
2
2
mn
= qol with I=
0₂ =
O₂ =
z
1
+ tan-¹
1
= [√m²
+
2π /m² +n²+1 m² +1
2
2
2
mn
√m² +n² +1,
F1)
1
n²+1
+ tan-¹
mn
F
√m² + n²+1,
2
2
where: qo: surface stress; m = x/z; n = y/z; x and y: length and width of the
uniformly loaded area
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