Anorexia Nervosa (AN) is a psychiatric condition leading to substantial weight loss among women who are fearful of becoming fat. Anarticle used whole-body magnetic resonance imagery to determine various tissue characteristics for both an AN sample of individualswho had undergone acute weight restoration and maintained their weight for a year and a comparable (at the outset of the study)control sample. Here is summary data on intermuscular adipose tissue (IAT; in kg).Condition Sample Size Sample Mean Sample SDAN160.520.26Control80.370.15Assume that both samples were selected from normal distributions. (b) Calculate an estimate for the difference between the true average AN IAT and true average control IAT, and do so in a way thatconveys information about the reliability and precision of the estimation. (Use a 99% confidence interval for 4AN - HcontrolRound your answers to two decimal places.)kgWhat does your estimate suggest about true average AN IAT relative to true average control IAT?O since this confidence interval includes zero, it is plausible that the true average AN IAT is greater than the true averagecontrol IAT are equal.Since this confidence interval includes only negative numbers, it is plausible that the true average AN IAT is less than thetrue average control IAT.Since this confidence interval includes only negative numbers, it is plausible that the true average AN IAT is greater thanthe true average control IAT are equal.Since this confidence interval includes zero, it is plausible that the true average AN IAT and true average control IAT areequal.Since this confidence interval includes only positive numbers, it is plausible that the true average AN IAT is greater thanthe true average control IAT are equal.

(b) The pooled variance is, sp2=n1-1s12+n2-1s22n1+n2-2=16-10.262+8-10.15216+8-2=1.171522=0.05325 The degrees of freedom is, df=n1+n2-2=16+8-2=22 Computation of critical value: The critical value of t-distribution for 0.01 level of significance at 22 degrees of freedom can be obtained using the excel formula “=T.INV.2T(0.01,22)”. The critical value is 2.8188.The 99% confidence interval for μAN-μcontrol is, CI=x¯1-x¯2±tα2sp21n1+1n2=0.52-0.37±2.81880.05325116+18=0.15±0.28=0.15-0.28,0.15+0.28=-0.13,0.43 Thus, the 99% confidence interval for μAN-μcontrol is (-0.13,0.43). It is clear that the confidence interval contains the value 0 which indicates that the true average AN IAT and true average control IAT are equal. Correct Answer: Since this confidence interval includes zero, it is plausible that the true average AN IAT and true average control IAT are equal.

Math

Statistics

Calculate an estimate for the difference between the true average AN IAT and true average control IAT, and do so in a way that conveys information about the reliability and precision of the estimation. (Use a 99% confidence interval for HAN - Hecontrol" Round your answers to two decimal places.) ) kg

Calculate an estimate for the difference between the true average AN IAT and true average control IAT, and do so in a way that conveys information about the reliability and precision of the estimation. (Use a 99% confidence interval for HAN - Hecontrol" Round your answers to two decimal places.) ) kg

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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