The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 794.6 792.5 794.2 794.4 790.8 793.8 B 800.1 789.8 794.4 793.5 796.0 793.4 (a) Why are these matched-pairs data? A. Two measurements (A and B) are taken on the same round. O B. All the measurements came from rounds fired from the same gun. O C. The measurements (A and B) are taken by the same instrument. O D. The same round was fired in every trial. (b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the a = 0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Let d, = A, - B,. ldentify the null and alternative hypotheses. Ho: Ha = 0 H: Ha * 0 Determine the test statistic for this hypothesis test. to = -0.83 (Round to two decimal places as needed.) Find the P-value. P-value = (Round three decimal places as needed.) %3D
The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data. Complete parts (a) through (d) below. Observation 1 2 3 4 5 6 794.6 792.5 794.2 794.4 790.8 793.8 B 800.1 789.8 794.4 793.5 796.0 793.4 (a) Why are these matched-pairs data? A. Two measurements (A and B) are taken on the same round. O B. All the measurements came from rounds fired from the same gun. O C. The measurements (A and B) are taken by the same instrument. O D. The same round was fired in every trial. (b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the a = 0.01 level of significance? Note: A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers. Let d, = A, - B,. ldentify the null and alternative hypotheses. Ho: Ha = 0 H: Ha * 0 Determine the test statistic for this hypothesis test. to = -0.83 (Round to two decimal places as needed.) Find the P-value. P-value = (Round three decimal places as needed.) %3D
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
Related questions
Question
- What is the P Value
- Reject H0?
- Construct a 99% confidence interval about the population
mean difference - Draw a boxplot of the differenced data. Does this visual evidence support the results obtained in part (b)?

Transcribed Image Text:The following data represent the muzzle velocity (in feet per second) of rounds fired from a 155-mm gun. For each round, two measurements of the velocity were recorded using two different measuring devices, resulting in the following data. Complete parts (a) through (d) below:
| Observation | 1 | 2 | 3 | 4 | 5 | 6 |
|-------------|------|------|------|------|------|------|
| A | 794.6| 792.5| 794.2| 794.4| 790.8| 793.8|
| B | 800.1| 789.8| 794.4| 793.5| 796.0| 793.4|
(a) Why are these matched-pairs data?
- A (correct answer): Two measurements (A and B) are taken on the same round.
- B: All the measurements came from rounds fired from the same gun.
- C: The measurements (A and B) are taken by the same instrument.
- D: The same round was fired in every trial.
(b) Is there a difference in the measurement of the muzzle velocity between device A and device B at the α = 0.01 level of significance? **Note:** A normal probability plot and boxplot of the data indicate that the differences are approximately normally distributed with no outliers.
Let dᵢ = Aᵢ - Bᵢ. Identify the null and alternative hypotheses.
- H₀: μd = 0
- H₁: μd ≠ 0
Determine the test statistic for this hypothesis test.
- t₀ = -0.83 (Round to two decimal places as needed.)
Find the P-value.
- P-value = 0.443 (Round to three decimal places as needed.)
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