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Calculate AG (in kJ) at 65 °C for the reaction: N₂O(0.0087 atm) + H₂(0.41 atm) + N₂(19.4 atm) +H₂O(1) Answer: -16.3 x

Calculate AG (in kJ) at 65 °C for the reaction: N₂O(0.0087 atm) + H₂(0.41 atm) + N₂(19.4 atm) +H₂O(1) Answer: -16.3 x

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
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Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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**Calculating ΔG and Vapor Pressure** 1. **Calculate ΔG (in kJ) at 65 °C for the reaction:** \[ \text{N}_2\text{O}(0.0087 \, \text{atm}) + \text{H}_2(0.41 \, \text{atm}) \rightleftharpoons \text{N}_2(19.4 \, \text{atm}) + \text{H}_2\text{O(l)} \] **Answer:** -16.3 kJ 2. **Calculate the vapor pressure of CH₃OH at 34 °C (in atm):** Assuming that the enthalpy change (ΔH°) and entropy change (ΔS°) of vaporization do not change significantly with temperature. \[ \text{CH}_3\text{OH (l)} \rightleftharpoons \text{CH}_3\text{OH (g)} \quad \Delta H^\circ = 38.0 \, \text{kJ} \quad \Delta S^\circ = 112.9 \, \text{J/K} \] (Do not round until the end. Using the exponent enlarges any round-off error.) **Answer:** 0.521 atm > **Note:** Ensure that calculations involving exponents and logarithms maintain precision to avoid enlarging round-off errors.
Transcribed Image Text:**Calculating ΔG and Vapor Pressure** 1. **Calculate ΔG (in kJ) at 65 °C for the reaction:** \[ \text{N}_2\text{O}(0.0087 \, \text{atm}) + \text{H}_2(0.41 \, \text{atm}) \rightleftharpoons \text{N}_2(19.4 \, \text{atm}) + \text{H}_2\text{O(l)} \] **Answer:** -16.3 kJ 2. **Calculate the vapor pressure of CH₃OH at 34 °C (in atm):** Assuming that the enthalpy change (ΔH°) and entropy change (ΔS°) of vaporization do not change significantly with temperature. \[ \text{CH}_3\text{OH (l)} \rightleftharpoons \text{CH}_3\text{OH (g)} \quad \Delta H^\circ = 38.0 \, \text{kJ} \quad \Delta S^\circ = 112.9 \, \text{J/K} \] (Do not round until the end. Using the exponent enlarges any round-off error.) **Answer:** 0.521 atm > **Note:** Ensure that calculations involving exponents and logarithms maintain precision to avoid enlarging round-off errors.
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