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Consider the combustion of methane. CH4 (9) + 2 O2(g) → CO2(g) +2 H2O(g) The reaction would have a vAS. Why?

Consider the combustion of methane. CH4 (9) + 2 O2(g) → CO2(g) +2 H2O(g) The reaction would have a vAS. Why?

Chemistry
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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the reaction would have a:

cant determine from the given information

negative

zero

positive

Consider the combustion of methane. CH4 (9) + 2 02(g) → CO2(g) +2 H20(g) The reaction would have a vAS. Why?
Transcribed Image Text:Consider the combustion of methane. CH4 (9) + 2 02(g) → CO2(g) +2 H20(g) The reaction would have a vAS. Why?
Consider the combustion of methane. CH(9) + 2 O2(g) — СО-(9) + 2 H:0(9) The reaction would have a vAS. JAS. Why? V -- The moles of gas increase. The number of moles are the same in reactants and products. The moles of gas decrease. The moles of reactant decreases. The moles of product increases. The moles of gas remain constant. Calculate the for the following process I P iumpCID II IC pu es.
Transcribed Image Text:Consider the combustion of methane. CH(9) + 2 O2(g) — СО-(9) + 2 H:0(9) The reaction would have a vAS. JAS. Why? V -- The moles of gas increase. The number of moles are the same in reactants and products. The moles of gas decrease. The moles of reactant decreases. The moles of product increases. The moles of gas remain constant. Calculate the for the following process I P iumpCID II IC pu es.
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