Calculate AG for the reaction 2 H₂S(g) + SO2(g) 3 Srhombic(s) + 2 H₂O(g) For the following conditions at 25°C: PH₂S=0.0004 atm Pso₂=0.0143 atm PH₂0=0.0162 atm AG = AG°f H₂S(g): = -34 kJ/mol SO2(g) = -300. kJ/mol H₂O(g) = -229 kJ/mol kJ Submit Answer 6 item attempts remaining Try Another Version
Calculate AG for the reaction 2 H₂S(g) + SO2(g) 3 Srhombic(s) + 2 H₂O(g) For the following conditions at 25°C: PH₂S=0.0004 atm Pso₂=0.0143 atm PH₂0=0.0162 atm AG = AG°f H₂S(g): = -34 kJ/mol SO2(g) = -300. kJ/mol H₂O(g) = -229 kJ/mol kJ Submit Answer 6 item attempts remaining Try Another Version
Chemistry & Chemical Reactivity
9th Edition
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Chapter18: Principles Of Chemical Reactivity: Entropy And Free Energy
Section18.5: Entropy Changes And Spontaneity
Problem 2RC
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![Calculate AG for the reaction
2 H₂S(g) + SO2(g) 3 Srhombic(s) + 2 H₂O(g)
For the following conditions at 25°C:
PH₂S=0.0004 atm
Pso₂=0.0143 atm
PH₂O=0.0162 atm
AG =
AGOf
H₂S(g):
SO2(g) = -300. kJ/mol
H₂O(g) = -229 kJ/mol
= -34 kJ/mol
KJ
Submit Answer
6 item attempts remaining
Try Another Version
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Transcribed Image Text:Calculate AG for the reaction
2 H₂S(g) + SO2(g) 3 Srhombic(s) + 2 H₂O(g)
For the following conditions at 25°C:
PH₂S=0.0004 atm
Pso₂=0.0143 atm
PH₂O=0.0162 atm
AG =
AGOf
H₂S(g):
SO2(g) = -300. kJ/mol
H₂O(g) = -229 kJ/mol
= -34 kJ/mol
KJ
Submit Answer
6 item attempts remaining
Try Another Version
Previous
Next
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