Important InformationAtomic Masses (g/mol): H = 1.01, C = 12.01, N = 14.01, O = 16.00,%DNe = 20.18, CI = 35.45, K = 39.10, Ar = 39.95,Cu = 63.55, Ag = 107.87%3D%3DwwmConstants:R = 8.314 J/mol·K = 0.08206 L·atm/mol·K%3Dww mwww mF = 96,485 C/mol = 96,485 J/V•mol%3D 4. a) Calculate AG° for the following reaction, using the provided information.2 C6H6(1) + 15 02(9)→ 12 CO2(9) + 6 H20 (g)AG°;(CO2(9) = -394. 6"/molAG°(H20(9) = -228.4(g)molAG°,(H20u) = -237.2 kmolkJAG°,(C,H6») = -121.7 K/тol

The balanced reaction given is, The data given for the standard formation free energies are,

Calculate AG° for the following reaction, using the provided information. 2 CoН6) + 15 02(9) — 12 СО2(9) + 6 H20(9) kJ AG°;(CO2(9) = -394.6 "/mol kJ AG°,(H20(9) = -228.4 mol kJ AG°;(H201) = -237.2 "/mol kJ mol AG°;(C6H6) = = -121.7

Calculate AG° for the following reaction, using the provided information. 2 CoН6) + 15 02(9) — 12 СО2(9) + 6 H20(9) kJ AG°;(CO2(9) = -394.6 "/mol kJ AG°,(H20(9) = -228.4 mol kJ AG°;(H201) = -237.2 "/mol kJ mol AG°;(C6H6) = = -121.7

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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Electrolysis

Electrolysis is defined as the process of breaking down ionic compounds into their constituent elements by passing a direct electric current through the compound in a fluid state. The cathode reduces cations, while the anode oxidizes anions. An electrolyte, electrodes, and some form of external power source are the main components required for conducting electrolysis. A partition, such as an ion-exchange membrane or a salt bridge, may also be used, but this is optional. These are primarily used to prevent the products from diffusing near the opposing electrode.

Question

Important Information
Atomic Masses (g/mol): H = 1.01, C = 12.01, N = 14.01, O = 16.00,
%D
Ne = 20.18, CI = 35.45, K = 39.10, Ar = 39.95,
Cu = 63.55, Ag = 107.87
%3D
%3D
wwm
Constants:
R = 8.314 J/mol·K = 0.08206 L·atm/mol·K
%3D
ww m
www m
F = 96,485 C/mol = 96,485 J/V•mol
%3D

4. a) Calculate AG° for the following reaction, using the provided information.
2 C6H6(1) + 15 02(9)
→ 12 CO2(9) + 6 H20 (g)
AG°;(CO2(9) = -394. 6
"/mol
AG°(H20(9) = -228.4
(g)
mol
AG°,(H20u) = -237.2 k
mol
kJ
AG°,(C,H6») = -121.7 K/
тol

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