Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![Given the following equilibrium constants at 431°C,
Na2 0(s) = 2 Na(1) + 02 (g) K1 = 7× 10-25
2
1
O2 (g)
NaO(g) = Na(l) +
K2 = 3 x 10-5
Na2 O2 (s) = 2 Na(1) + O2 (9)
K3 = 3 x 10-29
NaO2 (s) = Na(1) + O2 (9)
K4 = 4 x 10-14
determine the values for the equilibrium constants for the following reactions:
a. Na2 0(s) + 02 (g) = Na2 O2 (s)
2
Equilibrium constant =
b. NaO(g) + Na2 0(s) = Na2 O2 (s) + Na(1)
Equilibrium constant =
c. 2 NaO(g) = Na2 O2 (s)
Equilibrium constant =
(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F3b05a83d-4003-4223-8f12-2b20be1e7730%2F8fbad926-4853-4fec-80ca-ab4cdaa24314%2Faub0l4b_processed.png&w=3840&q=75)
Transcribed Image Text:Given the following equilibrium constants at 431°C,
Na2 0(s) = 2 Na(1) + 02 (g) K1 = 7× 10-25
2
1
O2 (g)
NaO(g) = Na(l) +
K2 = 3 x 10-5
Na2 O2 (s) = 2 Na(1) + O2 (9)
K3 = 3 x 10-29
NaO2 (s) = Na(1) + O2 (9)
K4 = 4 x 10-14
determine the values for the equilibrium constants for the following reactions:
a. Na2 0(s) + 02 (g) = Na2 O2 (s)
2
Equilibrium constant =
b. NaO(g) + Na2 0(s) = Na2 O2 (s) + Na(1)
Equilibrium constant =
c. 2 NaO(g) = Na2 O2 (s)
Equilibrium constant =
(Hint: When reaction equations are added, the equilibrium expressions are multiplied.)
Expert Solution
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Step 1 introduction
Given equilibrium reactions are
1. Na2O (s) <--> 2 Na (l) + 1/2 O2 (g) K1 = 7 x 10-25
2. NaO (g) <--> Na (l) + 1/2 O2 (g) K2 = 3 x 10-5
3. Na2O2(s) <--> 2 Na(l) + O2 (g) K3 = 3 x10-29
4. NaO2 (s) <--> Na(l) + O2 (g) K4 = 4 x10-14
If reactions added , the equilibrium expressions multiplied , if reaction is revesed K become reciprocated
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