Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
![**Transcription:**
Calculate \( K_{eq} \) for a \( \Delta G^\circ \) value of 6.9 kcal/mol at 25 °C.
**Explanation:**
This text presents a problem that involves calculating the equilibrium constant (\( K_{eq} \)) for a chemical reaction using the standard free energy change (\( \Delta G^\circ \)) value, which is given as 6.9 kcal/mol at a temperature of 25 °C. The calculation typically involves the relationship between \( \Delta G^\circ \) and \( K_{eq} \) given by the equation:
\[ \Delta G^\circ = -RT \ln K_{eq} \]
Where:
- \( \Delta G^\circ \) is the standard free energy change.
- \( R \) is the universal gas constant (1.987 cal/mol·K or 8.314 J/mol·K, depending on the units used).
- \( T \) is the temperature in Kelvin.
- \( K_{eq} \) is the equilibrium constant.
To solve this, convert 25 °C to Kelvin (298 K) and use the appropriate units for \( R \).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fdc1721bb-87af-4432-b926-b704463d725f%2F67d41447-211c-4c28-b58d-e62ef012e7ef%2F42h8hz_processed.jpeg&w=3840&q=75)
Transcribed Image Text:**Transcription:**
Calculate \( K_{eq} \) for a \( \Delta G^\circ \) value of 6.9 kcal/mol at 25 °C.
**Explanation:**
This text presents a problem that involves calculating the equilibrium constant (\( K_{eq} \)) for a chemical reaction using the standard free energy change (\( \Delta G^\circ \)) value, which is given as 6.9 kcal/mol at a temperature of 25 °C. The calculation typically involves the relationship between \( \Delta G^\circ \) and \( K_{eq} \) given by the equation:
\[ \Delta G^\circ = -RT \ln K_{eq} \]
Where:
- \( \Delta G^\circ \) is the standard free energy change.
- \( R \) is the universal gas constant (1.987 cal/mol·K or 8.314 J/mol·K, depending on the units used).
- \( T \) is the temperature in Kelvin.
- \( K_{eq} \) is the equilibrium constant.
To solve this, convert 25 °C to Kelvin (298 K) and use the appropriate units for \( R \).
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