c. Redraw the structures of the two conformations of galactosamine, but with the ring bonds all on the plane of the paper (like the structure shown in Problem #5b above). Clearly indicate the cis/trans relationships of the ring substituents using wedged or dashed lines as appropriate. Place your answers in the boxes below. Conformation 1: Conformation 2:

c. Redraw the structures of the two conformations of galactosamine, but with the ring bonds all on the plane of the paper (like the structure shown in Problem #5b above). Clearly indicate the cis/trans relationships of the ring substituents using wedged or dashed lines as appropriate. Place your answers in the boxes below. Conformation 1: Conformation 2:

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

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a. Use strain energy increments in the OWL Table Reference (see References button, Strain Energy Increments) to calculate the energy difference between the two chair conformations of the compound b. Specify substituent positions (axial or equatorial) in the more stable chair. c. Estimate the percent of the more stable chair at equilibrium at 25°C. (To determine the percent of the more stable chair at equilibrium, first calculate Keq, and then use this value to find the percentage.) CH3 CH3 Answers: a. The energy difference is b. In the more stable chair: • The phenyl group is in the • The isopropyl group is in the | kJ/mol. position. position. c. At 25°C the equilibrium percent of the more stable chair conformation is approximately [
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6. From the perspective of viewing down the C2-C3 bond, draw the Newman projection of the most stable conformation of 2, 3-dimethylbutane.
Several compounds are shown below. For each, make two models: one model of the compound as shown, and the other where each tetrahedral stereocenter is inverted. Compare the two models side-by-side to see if the model with the inverted stereocenter(s) is the enantiomer, or if it is identical to the original. Remember, you can rotate around o-bonds to place the molecule in the conformation with the highest symmetry. Is each compound meso or not? OH OH OH OH DOKOOK OH OH Compound 1 Compound 2 Compound 1's mirror image is identical to Compound 1 Compound 1's mirror image is the enantiomer of Compound 1 Compound 1 is meso Compound 2's mirror image is identical to Compound 2 Compound 2's mirror image is the enantiomer of Compound 2 Compound 2 is meso Compound 3's mirror image is identical to Compound 3 Compound 3's mirror image is the enantiomer of Compound 3 Compound 3 is meso Compound 4's mirror image is identical to Compound 4 Compound 4's mirror image is the enantiomer of Compound 4…
Part C. The constitution of ectocarpene a volatile, sperm-cell-attracting material released by the eggs of the seaweed Ectocarpus siliculosus is shown below. In ectocarpene, all of the C-C double bonds have cis geometric configurations and the chirality center has an (S) absolute con- figuration. Please draw a spatially accurate structural representation of ectocarpene. Condensed Formula CH3CH₂CH=CH-CHCH=CHCH₂CH=CHCH2 Structural Formula
See attached photo.
3. Circle all meso compounds ( H. CH3 H3C- HO- CH3 OH CH3 H. CH3 но CI- CH3 HO,