2. Draw the most stable conformer of the substituted cyclohexane shown below. OCH 3 HOW HO LOCH3 CH3 CH3 Extension: If the -OCH3 stereocentre was inverted (i.e. pointed in the opposite direction) would the resulting compound be more or less stable that the compound shown above? Explain your reasoning. Note this question is NOT asking whether the resulting conformer is more or less stable (it would be less, as the large -OCH3 group would be axial), but rather, the molecule overall. In the current molecule, the 'best case' conformer has 2/3 groups equatorial - the largest group and the smallest group. If the -OCH3 stereocentre was inverted, you could ring-flip to get a conformer that again has 2/3 groups equatorial, this time the largest 2. This would be more stable than the most stable conformer of the original molecule.
2. Draw the most stable conformer of the substituted cyclohexane shown below. OCH 3 HOW HO LOCH3 CH3 CH3 Extension: If the -OCH3 stereocentre was inverted (i.e. pointed in the opposite direction) would the resulting compound be more or less stable that the compound shown above? Explain your reasoning. Note this question is NOT asking whether the resulting conformer is more or less stable (it would be less, as the large -OCH3 group would be axial), but rather, the molecule overall. In the current molecule, the 'best case' conformer has 2/3 groups equatorial - the largest group and the smallest group. If the -OCH3 stereocentre was inverted, you could ring-flip to get a conformer that again has 2/3 groups equatorial, this time the largest 2. This would be more stable than the most stable conformer of the original molecule.
Organic Chemistry: A Guided Inquiry
2nd Edition
ISBN:9780618974122
Author:Andrei Straumanis
Publisher:Andrei Straumanis
Chapter6: Alkanes & Alkenes
Section: Chapter Questions
Problem 4E: Consider the molecule 1-bromo-2-methylbutane. C3 and C4 should be drawn as Et as in theexample. This...
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