(C) What final conversion can be achieved if a 72-dm^3 PFR is followed in series by a 24-dm^3 CSTR?
(C) What final conversion can be achieved if a 72-dm^3 PFR is followed in series by a 24-dm^3 CSTR?
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
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2 can u help me with part C using refereced data
![(C) What final conversion can be achieved if a 72-dm^3 PFR is followed in series by a 24-dm^3 CSTR?](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd47fc2c3-8f4b-4085-b234-bc909be774e3%2F420ffd60-0969-4631-aeab-79c9f054274e%2Fmcakr9_processed.png&w=3840&q=75)
Transcribed Image Text:(C) What final conversion can be achieved if a 72-dm^3 PFR is followed in series by a 24-dm^3 CSTR?
![XA
RATE
FAO/-RA 18000
(A) What are the PFR and CSTR volumes necessary to achieve a 40% for a single reactor process?
Perf Eq for CSTR
0
1
Perform Equation of a PFR
V
FAO
Reaction ASTILBENE → BTROSPHOPHENE + CMETHANE
FeedFlow Rate = 300.
=
0.2
1.67
10778.4
-TA
V
FAO
=
XAV=
Adiabatic & Exothermic
rxA dxA
SA
(-TA)
0.4
5
3600
mol
sec PureA
FAO
(-TA)
0.45
5
3600
FAO
→ V = √XA F40 dx
0 -TA
VCSTR
VPFR
,reference table.
= 4320 dm³
= 1440 dm³
0.5
5
3600
→ V =
0.6
5
3600
0.8
0.9
1.25
0.91
14400 19780.2
1
* 0.4 * 14400+ 0.4 * 3600
2](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fd47fc2c3-8f4b-4085-b234-bc909be774e3%2F420ffd60-0969-4631-aeab-79c9f054274e%2Fkf0xgi3j_processed.png&w=3840&q=75)
Transcribed Image Text:XA
RATE
FAO/-RA 18000
(A) What are the PFR and CSTR volumes necessary to achieve a 40% for a single reactor process?
Perf Eq for CSTR
0
1
Perform Equation of a PFR
V
FAO
Reaction ASTILBENE → BTROSPHOPHENE + CMETHANE
FeedFlow Rate = 300.
=
0.2
1.67
10778.4
-TA
V
FAO
=
XAV=
Adiabatic & Exothermic
rxA dxA
SA
(-TA)
0.4
5
3600
mol
sec PureA
FAO
(-TA)
0.45
5
3600
FAO
→ V = √XA F40 dx
0 -TA
VCSTR
VPFR
,reference table.
= 4320 dm³
= 1440 dm³
0.5
5
3600
→ V =
0.6
5
3600
0.8
0.9
1.25
0.91
14400 19780.2
1
* 0.4 * 14400+ 0.4 * 3600
2
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