### Analysis of Advertisement Position and Time Effects**(c) Significance Test of Advertisement Position**To test the significance of advertisement position effects with a significance level of α = 0.05:- **F statistic:** 149.14- **p-value:** Less than 0.001- **Decision:** Reject the null hypothesis- **Conclusion:** The position of the ads is important.**(d) Pairwise Comparisons Using Tukey's Method for Time of Day**Make pairwise comparisons of the morning, afternoon, and evening times using Tukey simultaneous 95% confidence intervals. Negative amounts should be indicated by a minus sign. Round your answers to two decimal places.- **Tukey q:** 3.53- **Mean Square Error (MSE):** 8.917Comparisons:- \( \mu_M - \mu_A = \) [Blank]- \( \mu_M - \mu_E = \) [Blank]- \( \mu_A - \mu_E = \) [Blank]**(e) Pairwise Comparisons Using Tukey's Method for Advertisement Positions**Make pairwise comparisons of the four ad positions using Tukey simultaneous 95% confidence intervals. Negative amounts should be indicated by a minus sign. Round your answers to two decimal places.Comparisons:- \( \mu_1 - \mu_2 = \) [Blank]- \( \mu_1 - \mu_3 = \) [Blank]- \( \mu_1 - \mu_4 = \) [Blank]- \( \mu_2 - \mu_3 = \) [Blank]- \( \mu_2 - \mu_4 = \) [Blank]- \( \mu_3 - \mu_4 = \) [Blank]**(f) Maximizing Consumer Response**Identify which time of day and advertisement position maximizes consumer response. Compute a 95% (individual) confidence interval for the mean number of calls placed for this optimal time and ad position. Round your answers to two decimal places.- **Confidence Interval:** - Lower Bound: [Blank] - Upper Bound: [Blank] **ANOVA Analysis of Telemarketing Response Rates Based on Time of Day and Advertisement Position**A telemarketing firm conducted a study to understand how two factors affect responses to television advertisements. The first factor is the time of day the ad is aired, while the second is the ad's position within the hour. Data is collected based on the number of calls to an 800 number after a sample broadcast.### Telemarketing Data Table#### Time of Day vs. Position of Advertisement- **10:00 (Morning)** - On the Hour: 42, 37, 41 - On the Half-Hour: 36, 38, 38 - Early in Program: 62, 64, 64 - Late in Program: 51, 48, 47- **4:00 (Afternoon)** - On the Hour: 60, 58, 60 - On the Half-Hour: 60, 55, 56 - Early in Program: 85, 80, 81 - Late in Program: 60, 67, 66- **9:00 (Evening)** - On the Hour: 102, 99, 97 - On the Half-Hour: 96, 91, 92 - Early in Program: 127, 120, 126 - Late in Program: 105, 101, 107### ANOVA: Two-Factor with Replication#### Summary- **Count**: 3 for each time block- **Sum and Average Responses**: - **Morning**: Sum = 575, Average = 47.92 - **Afternoon**: Sum = 799, Average = 66.58 - **Evening**: Sum = 1279, Average = 106.58 - **Total Average**: 73.72- **Variance**: - **Morning**: 16.58 - **Afternoon**: 132.45 - **Evening**: 106.58 - **Total Variance**: 625.03### ANOVA Output- **Source of Variation** - Sample: SS = 21506.89, df = 2, MS = 10780

a) Test of significance of time of day effects with α = .05. F-statistic = 1209.02 p-value =…

Answered: (c) Test the significance of position…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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We consider the differences between the reading and writing scores of a random sample of 200 students who took the High School and Beyond Survey. The mean and standard deviation of the differences are Xread = -0.531 and 8.858 points. write (a) Calculate a 95% confidence interval for the average difference between the reading and writing scores of all students. (Round your answers to two decimal places.) (b) Interpret this interval in context. (Round your answers to two decimal places.) We are 95% confident that on the reading test students score, on average, points lower to You may need to use the appropriate table in the Appendix of Tables to answer this question. points higher than they do on the writing test. (c) Does the confidence interval provide convincing evidence that there is a real difference in the average scores? Explain. Since 0 is included in the interval, the confidence interval does not provide convincing evidence that there is a real difference in the average scores.
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??
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