According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft ('Consumer fraud and,' 2008). Assume a state had 370 complaints of identity theft out of 1740 consumer complaints . Calculate a 93% confidence interval for the proportion of all complaints that are complaints of identity theft in that state. P: Parameter What is the correct parameter symbol for this problem? What is the wording of the parameter in the context of this problem? A: Assumptions Since information was collected from each object, what conditions do we need to check? Check all that apply. np≥10np≥10 n≥30n≥30 or normal population. n(pˆ)≥10n(p̂)≥10 n(1−pˆ)≥10n(1-p̂)≥10 N≥20nN≥20n n(1−p)≥10n(1-p)≥10 σσ is unknown. σσ is known. Check those assumptions: 1. nˆpnp^= which is 2. n(1−ˆp)n(1-p^)= which is 3. NN= which is If no N is given in the problem, use 1000000 N: Name the procedure The conditions are met to use a . I: Interval and point estimate The symbol and value of the point estimate on this problem are as follows: = Leave answer as a fraction. The interval estimate for is ( , ) Round endpoints to 3 decimal places. C: Conclusion We are % confident that is between % and %
According to the February 2008 Federal Trade Commission report on consumer fraud and identity theft, 23% of all complaints in 2007 were for identity theft ('Consumer fraud and,' 2008). Assume a state had 370 complaints of identity theft out of 1740 consumer complaints . Calculate a 93% confidence interval for the proportion of all complaints that are complaints of identity theft in that state.
P: Parameter
What is the correct parameter symbol for this problem?
What is the wording of the parameter in the context of this problem?
A: Assumptions
- Since information was collected from each object, what conditions do we need to check? Check all that apply.
- np≥10np≥10
- n≥30n≥30 or normal population.
- n(pˆ)≥10n(p̂)≥10
- n(1−pˆ)≥10n(1-p̂)≥10
- N≥20nN≥20n
- n(1−p)≥10n(1-p)≥10
- σσ is unknown.
- σσ is known.
Check those assumptions:
1. nˆpnp^= which is
2. n(1−ˆp)n(1-p^)= which is
3. NN= which is
If no N is given in the problem, use 1000000
N: Name the procedure
The conditions are met to use a .
I: Interval and point estimate
The symbol and value of the point estimate on this problem are as follows:
= Leave answer as a fraction.
The
Round endpoints to 3 decimal places.
C: Conclusion
- We are % confident that is between % and %
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