c)Suppose that the results of carrying out the hypothesis test lead to non-rejection of the nullhypothesis. Classify that conclusion by error type or as a correct decision if in fact the meanage at diagnosis of all people with early-onset dementia is less than 55 years old. Supposethat the manufacturer of a new COVID-19 vaccine in South Africa wants to test the nullhypothesis Ho: 0 = 0.90 against the alternative hypothesis H₁: 0 = 0.60. She defined her teststatistic Y as a number of patients recovered from COVID-19 after an observed twenty trials.If she decided to accept Ho and assume y > 14,i) What will be her Type I error and the power of the test.ii) Explain how the probability of Type II error can be reduced in this case and how it will affectType I error. Give a practical example.

Answered: Image /qna-images/answer/ccb08a76-373d-4bf8-b067-d87c6cb98b08.jpg

Answered: c) Suppose that the results of carrying…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Which of the following is the value necessary for rejection (or nonacceptance) of the null hypothesis? 1. The critical value 2. The obtained value 3. Type I error 4. Type II error
When the independent variable truly does alter the dependent variable scores (there is a significant effect), and our calculated test statistic does not exceed the critical cutoff value, we retain the null hypothesis when we should reject it. This kind of result is called? a.) a type 2 error b.) a type 1 error c.) a valid result d.) a large effect size
Suppose a hypothesis test was performed with a level of significance of 0.05. Then if the null hypothesis is actually true, then there is a 5% chance that the researcher will end up rejecting the null hypothesis in error. True False
6)
An institute conducted a clinical trial of its methods for gender selection. The results showed that 187 of 338 babies born to parents using a specific gender-selection method were boys. Use the sign test and a 0.01 significance level to test the claim that the method has no effect on the likelihood of a boy. Let p denote the population proportion of baby boys. Ignore the possibility of the method decreasing the likelihood of a boy. What are the null and alternative hypotheses? OA. Ho:p>0.5 H₁: p=0.5 OC. Ho: p=0.5 H₁: p20.5 B. Ho: p=0.5 H₁: p > 0.5 D. Ho: p=0.5 H₁: p=0.5 Find the test statistic. Test statistic = (Round to two decimal places as needed.)
A new drug is tested in two peer-reviewed studies, A and B. Both studies provide evidence that the new drug is an improvement (The null hypothesis, that the new drug does not help, is rejected). But the researchers who conducted study A report a p-value of 8.2%, the team from study B obtained a p-value of only 2.3%. Which study provides the stronger evidence in favor of the new drug? Choose the most appropriate answer. a. Study B, because follow-up studies usually provide stronger evidence. b. Study A, because their p-value is bigger. c. Study A, because it was done by real researchers, and B only by a 'team'. d. Study B, because their p-value is smaller. e. The evidence from both studies is too weak.
The manufacturer of a new antidepressant claims that, among all people with depression who use the drug, the proportion p of people who find relief from depression is at least 65%. A random sample of 170 patients who use this new drug is selected, and 100 of them find relief from depression. Based on these data, can we reject the manufacturer's claim at the 0.1 level of significance? State the null hypothesis H0 and the alternative hypothesis H1 Find the z test value Find the p-value Can we reject the claim that the proportion of people who find relief from depression using the new antidepressant is at least 65%? Yes or No?
An institute conducted a clinical trial of its methods for gender selection. The results showed that 153 of 276 babies born to parents using a specific gender-selection method were boys. Use the sign test and a 0.05 significance level to test the claim that the method has no effect on the likelihood of a boy. Let p denote the population proportion of baby boys. Ignore the possibility of the method decreasing the likelihood of a boy. What are the null and alternative hypotheses? O A. Ho: p=0.5 H₂₁: p20.5 O C. Ho: p=0.5 H₁: p=0.5 O B. Ho:p>0.5 H₁: p=0.5 O D. Ho: p=0.5 H₁: p > 0.5 Find the test statistic. Test statistic = Find the P-value. P-value = (Round to four decimal places as needed.) Determine the proper conclusion. Choose the correct answers below. Since the P-value is (Round to two decimal places as needed.) than the significance level, evidence that the method used is effective in increasing the likelihood of a boy. the null hypothesis. There is
A hospital claims that the mean wait time for emergency room patients is more than 38 minutes. Identify the null hypothesis Ho, and the alternate hypothesis Ha in terms of the parameter
According to the Centers of Disease Control, about 22% of American young people between the ages of 12 and 19 are obese.A student claims that the students in his local schools are in better shape than the national average, so their proportion of obese students is less than 22%. Which are the appropriate null and alternative hypotheses for this study? H0: p = 22%, HA: p < 22% H0: p ≠ 0, HA: p = 0 H0: p = 22%, HA: p > 22% H0: p = 22%, HA: p ≠ 22% Suppose that the result is to Fail to reject H0.Which is the proper conclusion? There is sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students. There is not enough information to answer this question. There is not sufficient evidence to support the claim that the students at his local schools have a smaller proportion of obese students.
A national poll found that 73% of US adults could distinguish the definition of astrology from astronomy. Hoping that the percentage for TU students is higher, the SGA polls a random sample to test the hypotheses where p = the true proportion of TU students who can distinguish the definition of astrology from astronomy. If the decision is "do not reject the null", the correct concluson to the hypothesis test is... There is convincing evidence that the proportion of TU students who can distinguish the definition of astrology from astronomy is more than 73%. There is not enough evidence to conclude that the proportion of TU students who can distinguish the definition of astrology from astronomy is more than 73%. There is convincing evidence that the proportion of TU students who can distinguish the definition of astrology from astronomy is equal to 73%. There is not enough evidence to conclude that the proportion of TU students who can…

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