(c) Show all steps to construct a 99% confidence interval estimate of the proportion of allhuman resource professional believing that the appearance of a job applicant is mostimportant for a good first impression. Check your solution using Excel and post ascreenshot on Crowdmark.(d) Construct an 80% confidence interval estimate of the proportion of all human resourceprofessional believing that the appearance of a job applicant is most important fora good first impression. Check your solution using Excel and post a screenshot onCrowdmark.(e) As the level of confidence decreases what happens to the width of the confidenceinterval?(f) If the level of confidence stays constant and the sample size increases what happensto the width of the confidence interval? 3. In a Harris poll of 514 human resource professionals, 90% said that the appearance of a jobapplicant is most important for a good first impression. Answer the following questionsby hand and post your solutions on Crowdmark.(a) Among the 514 human resource professionals who were surveyed, how many of themsaid that the appearance of a job applicant is most important for a good first impres-sion?(b) Verify that both np > 5 and nĝ > 5.

“Since you have posted a question with multiple sub-parts, we will solve first three subparts for…

Answered: (c) Show all steps to construct a 99%…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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You have these questions on your website, and you have the answer for 95%, please compute a 98% confidence interval. Only compute a 98% confidence interval. Cost to Repair Fire Damage, The mean cost to repair the smoke and fire damage that results from home fires of all causes is $11,389 (HomeAdvisor). How does the damage that results from home fires caused by careless use of tobacco compare? The file TobaccoFires provides the cost to repair smoke and fire damage associated with a sample of 55 fires caused by careless use of tobacco products. Using past years’ data, the population standard deviation can be assumed known with cr = $3027. What is the 95% confidence interval estimate of the mean cost to repair smoke and fire damage that results from home fires caused by careless use of tobacco? compute also a 98% confidence interval.
The local newspaper is conducting a poll about how the residents of the city feel about the traffic during rush hour. Of 666 people polled, 57 responded that they felt that it was manageable or tolerable. Calculate the margin of error in order to find the 95% confidence interval for the proportion of people who feel that the traffic during rush hour is tolerable.
could you please tell me how to explain to a friend who does not know anything about statistics the relationship between the confidence level expressed as a confidence interval and the level of significance in hypothesis testing. Illustrate the relationship using either the critical value or the p-value approach.thanks
Out of a sample of 650 high school students, 321 take the bus to school every day. Construct a 99% confidence interval for the population mean of high school students that take the bus to school every day. CI = (44.34%, 54.43%) CI = (45.54%, 53.23%) CI = (46.16%, 52.61%) CI = (43.23%, 51.18%)
Decide whether it describes a confidence interval for a proportion or a confidence interval for a mean. (b) Apply the correct formula to calculate the confidence interval in the format of an estimate + margin of error. During the 2016 season, Mark Williams played in 18 golf matches and used his driver club 126 times, hitting his drives an average of 278 yards per drive, with a standard deviation of 15 yards per drive. Calculate a 95% confidence interval for the distance he was able to hit his driver club in that season.
The following contingency table records some information about a sample of visitors to Old Fort William over a long weekend in August. Local Other Canadian Non-Canadian Total Young Child 40 75 35 150 Teen 25 50 20 95 Young Adult Mid Aged Adult 140 85 125 200 465 100 195 380 Senior Adult 120 165 125 410 Total 410 685 405 1500 Given the above information and choosing a level of significance of a = 0.01; you should reject the null hypothesis that there is at least one difference in origins among age groups that is statistically significant. True False
What do confidence intervals & hypothesis tests try to do?
qu2 Katrina wants to estimate the proportion of adults who read at least 10 books last year. To do so, she obtains a simple random sample of 100 adults and constructs a 95% confidence interval. Matthew also wants to estimate the proportion of adults who read at least 10 books last year. He obtains a simple random sample of 400 adults and constructs a 99% confidence interval. Assuming both Katrina and Matthew obtained the same point estimate, whose estimate will have the smaller margin of error? Justify your answer. Whose estimate will have the smaller margin of error and why? A. Katrina's estimate will have the smaller margin of error because the sample size is smaller and the level of confidence is lower. B. Matthew's estimate will have the smaller margin of error because the larger sample size more than compensates for the higher level of confidence. C. Katrina's estimate will have the smaller margin of error because the lower level of confidence…
The Pizza Shop wanted to determine what proportion of its customers ordered only cheese pizza. Out of 80 customers surveyed, 15 ordered cheese pizza. They want a 99% confidence interval of the true proportion of customers who order only cheese pizza. What is the 99% confidence interval of the true proportion of customers who order only cheese pizza? (0.075, 0.300) (0.115, 0.260) (0.086, 0.289) (0.102, 0.273)

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