The Pizza Shop wanted to determine what proportion of its customers ordered onlycheese pizza. Out of 80 customers surveyed, 15 ordered cheese pizza. They want a99% confidence interval of the true proportion of customers who order only cheesepizza.What is the 99% confidence interval of the true proportion of customers who orderonly cheese pizza?(0.075, 0.300)(0.115, 0.260)(0.086, 0.289)(0.102, 0.273)

Answered: The Pizza Shop wanted to determine what…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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Virginia wants to estimate the percentage of students who live more than three miles from the school. She wants to create a 95% confidence interval which has a margin of error of at most 5%. How many students should be polled to create the confidence interval? z0.10 z0.05 z0.025 z0.01 z0.005 1.282 1.645 1.960 2.326 2.576 Use the table of values above.
A research institute poll asked respondents if they felt vulnerable to identity theft. In the poll, n=935 and x=561 who said "yes." Use a 95% confidence level.
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Construct a 95% confidence interval for p1 - p2 for a survey that finds 30% of 240 males and 41% of 200 females are opposed to the death penalty. Group of answer choices a.(-0.200, -0.021) b.(-1.532, 1.342) c.(-1.324, 1.512) d.(-0.561, 0.651)
A new fertilizer was applied to the soil of 239 bean plants. 11% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval:
The question was asking for 99% confidence interval for pop
A new fertilizer was applied to the soil of 276 bean plants. 24% showed increased growth. Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer. Round all answers to 2 decimal places. Margin of Error (as a percentage): Confidence Interval: % to
A national polling organization conducted a survey asking people whether they would consider buying an electric car if petrol prices continue to rise. In the low-income sample of 200 people asked, 175 said they would not buy an electric car no matter how high petrol prices rise. In the high-income sample of 200 people asked, 127 responded the same. The 95% confidence interval for the difference in proportion of low income people and high income people who would never consider buying an electric car no matter how high the price of petrol got (rounded off to three decimals) is: A. [0.173 : 0.307] B. [0.145 : 0.335] C. [0.159 : 0.321] D. [0.172 : 0.308]
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A political candidate is told by his polling organization that a 90% confidence interval for the proportion of voters who support his candidacy is 0.49 + 0.05. What are the point estimate and margin of error for this interval? Point estimate = 0.44; margin of error = 0.05 Point estimate = 0.49; margin of error = 0.10 Point estimate = 0.44; margin of error = 0.10 Point estimate = 0.49; margin of error = 0.05 a b d.

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