Kim wants to determine a 95 percent confidence interval for the true proportion p of high school students in the area who attend their home basketball games. Out of randomly selected students she finds that that exactly half attend their home basketball games. About how large would have to be to get a margin of error less than 0.03 for p?

Q: A poll reported that 67.7% of adults in a certain country believe that organic produce is better for…

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Q: Kim wants to determine a 99 percent confidence interval for the true proportion of high school…

A: From the given information, Margin error (E) = 0.03 Assume sample proportion = 0.5   The objective…

Q: Out of a sample of 600 adults aged 18 to 30, 162 still lived with their parents. Based on this,…

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Q: 1. Find the 98% confidence interval (CI) and margin of error (ME) for the mean heights of men when:…

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Q: A poll reported that only 408 out of a total of 1549 adults in a particular region said they had a…

A: (a) Obtain the 95% confidence interval for the proportion that express a great deal or quite a lot…

Q: Suppose we wanted to estimate the average amount of sleep (in hours) a college student gets a night.…

A: Confidence interval : Confidence interval is a range of values it contains the true population…

Q: Kim wants to determine a 99% confidence interval for the proportion of high school students in a…

A: We have given that,  Population proportion (p) = 0.53, margin of error (E) = 0.03 and confidence…

Q: Kim wants to determine a 80 percent confidence interval for the true proportion of high school…

A: Given: Margin of error, E=0.04 Confidence level=80%

Q: A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of…

A: Solution: Given information: n1= 230 Sample size of people iving in Seattle n2= 172  Sample size of…

Q: Dylan wants to determine a 95% confidence interval for the true proportion of high school students…

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Q: Out of 240 sample students surveyed, 187 students are planning to take classes during the…

A: We have given that the sample size n=240 and favourable cases X=187. Sample proportion p^ = X/n.

Q: Suppose that the a college wants to have an idea of the average SAT score of the incoming freshman…

A: The confidence level is 0.90, the standard deviation is 310 and margin of error E is 50.

Q: For a sampling distribution of n = 500 and population proportion of 0.48 of those who prefer cookies…

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Q: In a class of 37 students, 47% of them said that math was their favorite subject. Construct an 85%…

A: n=37,p^=0.47α=0.15 Solution-: Let, X= Number of students said that math was their favorite subject…

Q: Beth wants to determine a 90% confidence interval for the proportion of high school students in a…

A: We have given that,  Population proportion (p) = 0.57, margin of error (E) = 0.04 and confidence…

Q: have to be to get a margin of error less than 0.02 for p?

A: confidence level=80% Margin of error(E)=0.02

Q: Kim wants to determine a 80 % confidence interval for the true proportion ? of high school students…

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Q: A survey of 26 individuals found that they spent an average of $39.21 on exercise attire for the…

A: Confidence interval is an inference process which is used to estimate the population parameter. The…

Q: Suppose you want to construct a confidence interval with a margin of error of 0.03 (3%). Find the…

A: The formula for calculating sample size is, n = z2*p^(1-p^)MOE2 Where, z is the z score (default…

Q: A study at Harvard found that 44% of their students binge drink. You are at Princeton doing a…

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Q: Hearts College found that 50 students out of a sample of 600 students take the subway to school.…

A: Given data is fit for difference of proportions. we need to find the confidence interval for 90%.

Q: In a clinical trial of a certain drug, 27 subjects experience headaches among the 219 subjects…

A: From the given information,

Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: A recent study indicated that 24% of women over 55 are widows. A researcher wishes to estimate with…

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Q: Javier wants to estimate the percentage of people who have purchased a used car. He surveys 250…

A: From the provided information, Sample size (n) = 250 From which 212 have purchased a used car.…

Q: Suppose that you are in charge to see if dropping a computer will damage it. You want to find the…

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Q: What proportion of college students earn their undergraduate degrees in four years? A college…

A: The formula of the margin of error when the limits given are,

Q: We wish to estimate what percent of adult residents in a certain county are parents. Out of 100…

A: According to the given information, we have Out of 100 adult residents sampled, 88 had kids. 99%…

Q: Suppose you calculate a 95% confidence interval for a proportion to to be: 0.39 to 0.78. Determine…

A: Given,   Lower bound = 0.39​ Upper bound = 0.78   Here, we use to determine the margin of error.

Q: If n = 15, the sample mean = 150, SD = 10, what is the confidence interval (using 99% confidence…

A: Given data,n=15x=150σ=10z-value at 99% confidence is Zc=2.576

Q: Beth wants to determine a 99 percent confidence interval for the true proportion p of high school…

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Q: Dylan wants to determine a 99 percent confidence interval for the true proportion p of high school…

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Q: If n = 380 and X = 304, construct a 95% confidence interval for the population proportion, p. Give…

A: Given: n = 380 x = 304

Q: Out of 300 people sampled, 24 had kids. Based on this, construct a 95% confidence interval for the…

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Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

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Q: The police department wants to reduce the margin of error for their 95% confidence interval. If they…

A: Here Given  The police department wants to reduce the margin of error for their 95% confidence…