A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of 172 people in Spokane found that 47 of them had a pet. Let p-hat 1 be the proportion of pet-owners in Seattle and p-hat 2 be the proportion of pet owners in Spokane. Find an 80% confidence interval for the difference in proportions. Use three decimals when computing the proportions and give your final answer to three decimal places.
A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of 172 people in Spokane found that 47 of them had a pet. Let p-hat 1 be the proportion of pet-owners in Seattle and p-hat 2 be the proportion of pet owners in Spokane. Find an 80% confidence interval for the difference in proportions. Use three decimals when computing the proportions and give your final answer to three decimal places.
MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
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A random sample of 230 people living in Seattle found that 83 of them had a pet. A random sample of 172 people in Spokane found that 47 of them had a pet. Let p-hat 1 be the proportion of pet-owners in Seattle and p-hat 2 be the proportion of pet owners in Spokane. Find an 80% confidence interval for the difference in proportions.
Use three decimals when computing the proportions and give your final answer to three decimal places.
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