A new fertilizer was applied to the soil of 226 bean plants.  85% showed increased growth.  Find the margin of error and 95% confidence interval for the percentage of all bean plants which show increased growth after application of the fertilizer.     margin of error as a percentage  confidence interval % to %

Q: Of 500 random people surveyed, 72 were smokers.  Find the 95% confidence interval. SE=0.0157

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Q: In a survey of 2591 adults in a recent​ year 1414, say they have made a New​ Year's resolution.…

A: From the provided information,Confidence level = 90% and 95%

Q: In a survey of 3001 ​adults, 1486 say they have started paying bills online in the last year.…

A: Assuming that the number of people paying bills online has a binomial distribution with n=3001, and…

Q: A survey of 700 non-fatal accidents showed that 167 involved uninsured drivers. Construct a 99%…

A: Given data,n=700x=167Point estimate isp=xn=167700=0.2386Construct a 99% confidence interval?

Q: In a survey of 2274 adults, 749 say they believe in UFOs. Construct a 99% confidence interval for…

A:

Q: In a survey of 2000 adults in a recent​ year, 708 made a New​ Year's resolution to eat healthier.…

A: Confidence interval for population proportion is given by, p^ +- z* √(pq/n) At 90% z = 1.645 At 95%…

Q: I want to estimate the population mean number of times people walk their dogs in a day In my…

A: Given information- Sample size, n = 5 Calculating sample mean and sample standard deviation using…

Q: in a survey of 2042 adults in a recent​ year, 715 made a New​ Year's resolution to eat healthier.…

A:

Q: Find the critical value, for a 90% confidence when the sample size is 22.

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Q: If n=590 and p=0.93, construct a 90% confidence interval.

A: Express the expression for the confidence interval. C.I=p±Z*p(1-p)n Here, Z* is the critical value .…

Q: Emma wants to estimate the percentage of people who use public transportation in a city. She surveys…

A: Obtain the margin of error. The margin of error is obtained below: The formula for the margin of…

Q: When 290 college students are randomly surveyed, it is found that 120 own a car. Find a 99%…

A: Given that, x=120,n=290 The sample proportion is, Critical values: By using the standard normal…

Q: Identify the t-score for a 90% confidence interval if the sample size is 31. t =

A: c1=90%n=31α=1-0.90=0.10df=n-1=31-1=30

Q: business conducts a random sample of 89 of its customers and find that 44 of them think the company…

A:

Q: The 95​% confidence interval for the proportion that express a great deal of confidence or quite a…

A: A poll reported that only 645 out of a total of 2029 adults in a particular region said they had a​…

Q: Construct a​ 99% confidence interval for the population proportion. Interpret the results.

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Q: A researcher wanted to compare the percentages of men and women who play the lottery.  They randomly…

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Q: t has been determined with 95% confidence that the proportion of Americans who eat turkey on…

A: The 95% confidence that the proportion of Americans who eat turkey on Thanksgiving is between 0.78…

Q: In a survey of 2013 adults in a recent​ year, 731 made a New​ Year's resolution to eat healthier.…

A:

Q: Data of the weights of 81 pet dogs was collected. The sample mean was 30. The standard deviation is…

A: Here, T - interval is applicable ================= df = n-1

Q: The FBI wants to determine the effectiveness of their 10 Most Wanted list. To do so, they need to…

A:

Q: A survey showed 980 of 1500 adult respondents believe in global warming. Construct a 95% confidence…

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Q: If a 90%, a 95% and a 99% confidence interval are foung for a population mean, describe how the 3…

A: Population mean CI for known population standard deviation is, CI=x¯±Zσnwhere,σ=population standard…

Q: Out of 100 people sampled, 54 had kids. Based on this, construct a 90 % confidence interval for the…

A:

Q: Out of 400 people sampled, 276 had kids. Based on this, construct a 90% confidence interval for the…

A: For 90% confidence intervalα=1-CI=1-0.90=0.10So, zα2=z0.102=z0.05=1.645

Q: In a survey of 2947 ​adults, 1430 say they have started paying bills online in the last year.…

A: X = 1430 N = 2947 99% confidence level

Q: If n= 100 and x= 80, construct a 99% confidence interval.  Give your answers to three decimals

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Q: A random sample of high school seniors were asked whether they were applying for college. The…

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Q: In a survey of 2033 adults in a recent​ year, 735 made a New​ Year's resolution to eat healthier.…

A: First find out the true population proportion .    Total number of adults in a survey = n= 2033…

Q: Find z* for a confidence level of 83%. Give your answer to 3 decimal places.

A: We have to find z* for a confidence level of 83%

Estimation

A new framework of data analysis where the new statistical methods are used for interpreting the results and analyzing the data is known as estimation in statistics.