Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer C :
![## Using the Voltaic Cell Below:
### A) Write the equation for this cell.
### B) Calculate the standard cell potential (E°).
### C) Calculate the voltage for this cell.
### D) Diagram Analysis
In the above diagram:
- **Left Compartment:** Contains an Al (Aluminum) electrode immersed in a solution of \(Al^{3+}\) ions with a concentration of 0.435 M
- **Right Compartment:** Contains a Sn (Tin) electrode immersed in a solution of \(Sn^{2+}\) ions with a concentration of 0.00212 M
Both compartments are separated by a **Porous Barrier**. A voltmeter (V) is connected to measure the potential difference between the two electrodes.
**Anode and Cathode Identification:**
- **Anode:** The electrode where oxidation takes place. Historically, this is the electrode losing electrons.
- **Cathode:** The electrode where reduction takes place. Historically, this is the electrode gaining electrons.
**Flow of Electrons:**
- The electrons flow from the anode to the cathode through the external circuit, which is through the wire connecting the electrodes.
### E) Write the cell diagram.
---
**Diagram Explanation:**
A schematic representation includes the following components:
- A left half-cell containing the aluminum electrode (labeled "Al") in a solution of \(Al^{3+}\) ions (0.435 M).
- A right half-cell containing the tin electrode (labeled "Sn") in a solution of \(Sn^{2+}\) ions (0.00212 M).
- A porous barrier separating both half-cells to prevent the mixing of different solutions.
- A voltmeter (labeled "V") connecting the aluminum and tin electrodes, measuring the potential difference.
- The flow of electrons is indicated by an arrow pointing from the Aluminum electrode (Anode where oxidation occurs) to the Tin electrode (Cathode where reduction occurs).](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2F43ef5448-495e-49e8-9cec-405cabc5c22f%2F9b0ab155-e0be-4ec5-8aee-9a19ae6ac6e0%2F14k6aek.jpeg&w=3840&q=75)
Transcribed Image Text:## Using the Voltaic Cell Below:
### A) Write the equation for this cell.
### B) Calculate the standard cell potential (E°).
### C) Calculate the voltage for this cell.
### D) Diagram Analysis
In the above diagram:
- **Left Compartment:** Contains an Al (Aluminum) electrode immersed in a solution of \(Al^{3+}\) ions with a concentration of 0.435 M
- **Right Compartment:** Contains a Sn (Tin) electrode immersed in a solution of \(Sn^{2+}\) ions with a concentration of 0.00212 M
Both compartments are separated by a **Porous Barrier**. A voltmeter (V) is connected to measure the potential difference between the two electrodes.
**Anode and Cathode Identification:**
- **Anode:** The electrode where oxidation takes place. Historically, this is the electrode losing electrons.
- **Cathode:** The electrode where reduction takes place. Historically, this is the electrode gaining electrons.
**Flow of Electrons:**
- The electrons flow from the anode to the cathode through the external circuit, which is through the wire connecting the electrodes.
### E) Write the cell diagram.
---
**Diagram Explanation:**
A schematic representation includes the following components:
- A left half-cell containing the aluminum electrode (labeled "Al") in a solution of \(Al^{3+}\) ions (0.435 M).
- A right half-cell containing the tin electrode (labeled "Sn") in a solution of \(Sn^{2+}\) ions (0.00212 M).
- A porous barrier separating both half-cells to prevent the mixing of different solutions.
- A voltmeter (labeled "V") connecting the aluminum and tin electrodes, measuring the potential difference.
- The flow of electrons is indicated by an arrow pointing from the Aluminum electrode (Anode where oxidation occurs) to the Tin electrode (Cathode where reduction occurs).
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