By referring to USCS table 1 (below), what is the soil type if theresults from sieve test show; i. Less than 5% of soil passingNo.200 sieve, ii. Less that 50% of soil passing No. 4 sieve, andiii. Cu is 5 and Cc is 2. (Answer in symbol only i.e. SP, SW)Major divisionTypical nameClassification criteriaGroupEymbalGWWel-graded gravels and gravel-sand mitures, inte or no finesU- DJD, greater than 4C-0»(O x O between 1 and 3.GPPoorly-graded 9graveis andgravel-sand mixtures, inte orno fines.Not meeting both criteria for GW.Sity gravels. gravel-sand-sitmoturesGMAlterberg limits plot below A-ine orplasticity index less than 4.ClayeymituresGCAlterberg limits piot above Aine orplasticity index less than 4.SwWel-graded sands and gravellysands, itte or no fines.U greater than 6C, between 1 and 3Not meeting both criteria for SW.Poorly-graded sandsgravelly sands, tle or no fines.SPandSMAttorberg imits plot below A-ine orplasticity index less than 4.Sity sands, and-sit mitures.Clayeymitures.sands.Aterberg limits plot above A-ine orplasticity index greater than 7.sCsand-clayML Inorganic sits, very fine sands, rock flour, sity or clayeyfine sands.Inorganic clays or low to medium plasticity, gravely clays.sandy clays, silty clays, lean clays.Organic sits and organic sity cays of low plasticity.CLOLCheck Plasticity ChartMH Inorganic sits, micaceous or diatomaceous fine sands orsits, elastic sitsCH Inorganic clays of high plasticity. tat clays.OH Organic clays of medium to high plasticity.Highly organic claysP,Peat, muck and other highly organic soils.Fibrous organic mater, will char, burn, or glow.Readily identified by colour, odour, spongy teet andforous texture.Note: Boundary elassification Sols possessing characteristics of two groups are designated by combinations ef group symbols-kor eanple, GWGC, wel graded, gavelsand miture with diay binder(More than 50% retained on No. 200 ASTM sieve)Sos poueseseo)No. 200 ASTM Sieve)sossed euou o soG)spues"No 4 ASTM sievesyaugASTM s Na 4Sits andpur suSqu pronspuesleve GW. GP SW. SP. Moe thao 12%passing No. 200 ASTM sieve- GM, GC.SM, SC. 5% 1o 12% passing No. 200 ASTMsal symbols.en Bunbes uogeoynsep ouepuognas

Less than 5% of soil passing NO 200 sieve it means more than 50% of soil are retained on NO 200…

By referring to USCS table 1 (below), what is the soil type if the results from sieve test show; i. Less than 5% of soil passing No.200 sieve, ii. Less that 50% of soil passing No. 4 sieve, and iii. Cu is 5 and Cc is 2. (Answer in symbol only i.e. SP, SW)

By referring to USCS table 1 (below), what is the soil type if the results from sieve test show; i. Less than 5% of soil passing No.200 sieve, ii. Less that 50% of soil passing No. 4 sieve, and iii. Cu is 5 and Cc is 2. (Answer in symbol only i.e. SP, SW)

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

See similar textbooks

Related questions

Q: The sieve analysis of three soils and the liquid limits and plastic limits of the fraction passing…

A: Group index value: 0≤G.I≤20.. so when you get negative value , G.I = 0 when you get more than 20…

Q: Do the following: a) Calculate the percent retained and percent passing each sieve, and graph the…

Q: ple from a site in Escondido was sieved in the lab. The entire sample h which 1200 grams passed the…

Q: Determine : 1. Soil classification of soil A using AASHTO method. 2. Soil classification of soil B…

A: 1. Soil A according to AASHTO: The AASHTO classification chart is shown below: Given data, Passing…

Q: The sieve analysis of three soils and the liquid limits and plastic limits of the fraction passing…

A: Step-1For Soil-BThe % passing through 200=80%>35%So Silt-Clay mineral group

Q: Can I get a step by step for this question? Using the data presented for the given soil sample,…

A: Given data: Soil is Inorganic, Liquid limit=20% Plastic Index=6% Coefficient of uniformity, Cu=5.5…

Q: EXERCISE 2 Results from a grain-size (sieve) analysis of a given soil are tabulated below. The soil…

A: Given, Sieve analysis data LL = 23% PL = 19%

Q: Help me and show me the steps to Classify the soil by the AASHTO system.

A: The objective of the question is to classify the given soil sample using the AASHTO (American…

Q: A Sample of soil was tested in the laboratory with the following results Liquid limit =30% Plastic…

A: we have Liquid limit =30% Plastic limit =12% U.S. Sieve Size Percentage Passing…

Q: Consider the grain size gradation curve for the soil shown in the image below and classify the soil…

A: Look at the % passing through sieve no 200=20<50%⇒COARSE GRAINED SOIL

Q: Soil 1 Diameter or Sieve No. Mass Retained Soil 2 Diameter or Sieve No. Mass Retained (g) (g) % in ½…

A: American Association of State Highway and Transport Officials (AASHTO) and Unified soil…

Q: Q2 The figure below gives the grain-size distribution of two soils. 100 Soil A 60 Soil B 40 1.0 0.1…

A: For soil AA: D10=0.09 D30=0.11 D60=0.13 Cu=0.13/0.09=1.44<6

Q: 16. The results for sieve analysis is shown in the following table: Sieve No. 4 10 20 40 60 100 200…

Q: 3. The sieve analysis data for a granular soil are given below. %passing 19mm sieve = 100 %passing…

A: Step 1

Q: EXERCISI Results from a grain-size (sieve) analysis of a given soil are tabulated below. The soil…

A: Given information, WL = 23% P.L = 19%

Q: Mechanical analysis on four different samples designated as A, B, Cand D were carried out in a soil…

Q: The following information is given about a soil sample: 7% retained on a No. 4 seive 15% pass a No.…

A: Percentage retained on No.4 sieve = 7% Percentage passing on No. 200 sieve = 15% Plasticity index =…

Concept explainers

Soil classification and characteristics

Soil classification is a method of categorizing soil based on its properties, types, and uses. The motive of soil classification is to arrange various types of soils and divide them into groups for various engineering and agricultural purposes. Soil classification is carried out by various agencies as per their purposes. From an engineering perspective, soil classification is done to find out the suitability of soil for various construction purposes like the construction of dams, foundations, highways, infrastructures, and so on. For engineering purposes, the soil is classified by the following systems:

Question

By referring to USCS table 1 (below), what is the soil type if the
results from sieve test show; i. Less than 5% of soil passing
No.200 sieve, ii. Less that 50% of soil passing No. 4 sieve, and
iii. Cu is 5 and Cc is 2. (Answer in symbol only i.e. SP, SW)
Major division
Typical name
Classification criteria
Group
Eymbal
GW
Wel-graded gravels and gravel-
sand mitures, inte or no fines
U- DJD, greater than 4
C-0»(O x O between 1 and 3.
GP
Poorly-graded 9graveis and
gravel-sand mixtures, inte or
no fines.
Not meeting both criteria for GW.
Sity gravels. gravel-sand-sit
motures
GM
Alterberg limits plot below A-ine or
plasticity index less than 4.
Clayey
mitures
GC
Alterberg limits piot above Aine or
plasticity index less than 4.
Sw
Wel-graded sands and gravelly
sands, itte or no fines.
U greater than 6
C, between 1 and 3
Not meeting both criteria for SW.
Poorly-graded sands
gravelly sands, tle or no fines.
SP
and
SM
Attorberg imits plot below A-ine or
plasticity index less than 4.
Sity sands, and-sit mitures.
Clayey
mitures.
sands.
Aterberg limits plot above A-ine or
plasticity index greater than 7.
sC
sand-clay
ML Inorganic sits, very fine sands, rock flour, sity or clayey
fine sands.
Inorganic clays or low to medium plasticity, gravely clays.
sandy clays, silty clays, lean clays.
Organic sits and organic sity cays of low plasticity.
CL
OL
Check Plasticity Chart
MH Inorganic sits, micaceous or diatomaceous fine sands or
sits, elastic sits
CH Inorganic clays of high plasticity. tat clays.
OH Organic clays of medium to high plasticity.
Highly organic clays
P,
Peat, muck and other highly organic soils.
Fibrous organic mater, will char, burn, or glow.
Readily identified by colour, odour, spongy teet and
forous texture.
Note: Boundary elassification Sols possessing characteristics of two groups are designated by combinations ef group symbols-kor eanple, GWGC, wel graded, gavel
sand miture with diay binder
(More than 50% retained on No. 200 ASTM sieve)
Sos poueseseo)
No. 200 ASTM Sieve)
sossed euou o soG)
spues
"No 4 ASTM sieve
syaug
ASTM s Na 4
Sits and
pur suS
qu pron
spues
leve GW. GP SW. SP. Moe thao 12%
passing No. 200 ASTM sieve- GM, GC.
SM, SC. 5% 1o 12% passing No. 200 ASTM
sal symbols.
en Bunbes uogeoynsep ouepuognas

Expert Solution

This question has been solved!

Explore an expertly crafted, step-by-step solution for a thorough understanding of key concepts.

This is a popular solution!

SEE SOLUTION Check out a sample Q&A here

Step 1

VIEW

Step 2

VIEW

Trending now

This is a popular solution!

Step by step

Solved in 2 steps

SEE SOLUTION Check out a sample Q&A here

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, civil-engineering and related others by exploring similar questions and additional content below.

Similar questions

Soils Mechanics Answer exercise 3
The sieve analysis data for a granular soil are given below. % passing 76.2 mm sieve = 98 % passing 4.75 mm sieve = 63 % passing 0.075 mm sieve = 18 What would be the percentage of fine fraction by the USCS system? а. 18% оБ. 16% O c. 63% O d. 35% e. 98%
Classify the soil by the Unified classification system. The results of the particle-size analysis of a soil are as follows: Percent passing through the No. 10 sieve = 90% Percent passing through the No. 40 sieve = 65% Percent passing through the No. 200 sieve = 15% The liquid limit and plasticity index of the minus No. 40 fraction of the soil are 35 and 15, respectively. Note: Solution is not required for PS3. Enter your answers here: Group symbol (all upper case) = Group name (all lower case) =
Percent Passing (by weight) You are provided the mechanical sieve/hydrometer and Atterberg Limit test results for three soils, labeled as Soil #1, Soil #2, and Soil #3. The mechanical sieve results are shown in Figure 1, while Table 2 presents the Atterberg Limit test results. Classify the soils in accordance with the Unified Soil Classification System (USCS) and AASHTO. 100 90 80 60 50 40 30 20 10 0 0.0001 CLAY SIZE Soil #3 Soil #2 Soil #1 0.001 } Soil #1 #2 SILT SIZE #3 0.01 0.1 Grain Size (mm) Figure 1. Mechanical Sieve and Hydrometer Results for Problem #2. 0.075 mm Table 2. Atterberg Limits (ASTM D4318) for Problem #2. LL 68 39 SAND SIZE ΝΑ 1 PL 19 31 ΝΑ GRAVEL 10
The laboratory test results of six soils are given in the following table. Classify the soils by the AASHTO Soil Classification System and give the group indices. Sieve Analysis-Percent Passing Soil Sieve No. C D A в F 4 100 100 95 95 100 100 10 95 80 80 90 94 94 40 82 61 54 79 76 86 200 65 55 8 64 33 76 Liquid limit 42 38 NP* 35 38 52 Plastic limit 26 25 NP 26 25 28 *NP = nonplastic
How to layout simple curves by Deflection Angles? Outline the step by step process and show a schematic diagram.
SITUATION 1 The sieve analysis of three soils and the liquid and plastic limits of the fraction passing no.40 Classify each soil using AASHTO classification system. ( sieve are given below. each Sieve Analysis Diameter Percent Finer (%) Sieve No. (mm) A 4 4.750 90 100 100 8 2.360 64 90 100 10 2.000 54 77 98 20 0.850 34 59 92 40 0.425 22 51 84 60 0.250 17 42 79 100 0.150 9. 35 70 200 0.075 33 63 Characteristics of fraction passing no.40 sieve LL 35 46 47 PL 29 29 24
1. Sieve analysis data for two inorganic soils are provided in Table 1. Soil 1 has LL = 64 and PL = 38. Soil 2 has LL = 26 and PL =18. To plot the particle size distribution curves for Soils 1 and 2 using the attached sheet. Determine the effective grain size, D10 for Soil 2. Determine the USCS designation for each soil. List step by step how you make your choices. Table 1. Sieve Analysis Data. Sieve No. 14 10 20 40 60 100 200 Mesh opening (mm) 4.750 2.000 0.850 98 0.425 93 0.250 88 0.150 83 0.075 77 Soil 1 % finer 100 100 Soil 2 % finer 100 90 64 38 29 21 11
show your solutions
- Once answered correctly will UPVOTE!!
Someone can help me with this one please.
How to solve 5.6 part A & B