بوالو CONSERVATION OF +V MOMENTUM (NAVIER- STOKES) r ər д 10 + Share √z (r) =√o = 0 1 ǝ² / 2 av ǝ²✓ ((ry.). Portrar д др 2(10 +V. pg, +μ dz dr ar Ve 1 др + +V. r ᎧᎾ др 10 dv. 1 + +V. H +μ r + Ir de rar dr r ᎧᎾ + Y₁ ar + Tr 20 ↑ +1 STEADY-STATE + P80+μ dr r dr 90² r² Do + + dz² 1 J² 2 dv/ d² v + 962 + до де IL N = 0 => f f(r) ар ≥ 31 = 412 (1317) 20170 az Ө 24 20 =0 => P+ f (o) BCS (1)@=a, √z=0 (2) @r=0, √z = FINITE
بوالو CONSERVATION OF +V MOMENTUM (NAVIER- STOKES) r ər д 10 + Share √z (r) =√o = 0 1 ǝ² / 2 av ǝ²✓ ((ry.). Portrar д др 2(10 +V. pg, +μ dz dr ar Ve 1 др + +V. r ᎧᎾ др 10 dv. 1 + +V. H +μ r + Ir de rar dr r ᎧᎾ + Y₁ ar + Tr 20 ↑ +1 STEADY-STATE + P80+μ dr r dr 90² r² Do + + dz² 1 J² 2 dv/ d² v + 962 + до де IL N = 0 => f f(r) ар ≥ 31 = 412 (1317) 20170 az Ө 24 20 =0 => P+ f (o) BCS (1)@=a, √z=0 (2) @r=0, √z = FINITE
Introduction to Chemical Engineering Thermodynamics
8th Edition
ISBN:9781259696527
Author:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Publisher:J.M. Smith Termodinamica en ingenieria quimica, Hendrick C Van Ness, Michael Abbott, Mark Swihart
Chapter1: Introduction
Section: Chapter Questions
Problem 1.1P
Related questions
Question
How they find z value. Show that as well as explain
Please explain r and teta too.
![Applying the Navier-Stokes Equations, part 4 - Lecture 4.9-Chemical Engineering Flui
chanics
Share
CONSERVATION OF MOMENTUM (NAVIER-STOKES) Uz (r) √=√0=0
др
10
DCA***CERE
+V
dr
av
+
+v.
dz
ve
+
+
ᎧᎾ
VV
dr
pg,
1 др
dr r dr
a
1 д
+
18² / 2 av 3² √√]
r² 90² r² Do dz²
y
+
2 ǝv/ a²v
-(rv +
1 a²
((())
ZP
ǝt
at
+
三十
ǝr Trǝe
STEADY-STATE
ар
r
Z
= 0
2P
+ +V₂
αν др
Əz
=> f f(r)
где
+
+
+
arrǝr r² 90² r² do dz²
10 dv. 1 ² ²
+ ]
32 = 41 31 (1317)
az
r Ər
r
ər
24
20
=0 => P + f (o)
BCS (1) @ra, √z=0
(2) @r=0, √z = FINITE](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Ff5fc9088-6d0a-4312-bffe-77961b56b51f%2Fdd54682c-cd41-4e24-b344-c438de0abf6f%2Ffbo3m2l_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Applying the Navier-Stokes Equations, part 4 - Lecture 4.9-Chemical Engineering Flui
chanics
Share
CONSERVATION OF MOMENTUM (NAVIER-STOKES) Uz (r) √=√0=0
др
10
DCA***CERE
+V
dr
av
+
+v.
dz
ve
+
+
ᎧᎾ
VV
dr
pg,
1 др
dr r dr
a
1 д
+
18² / 2 av 3² √√]
r² 90² r² Do dz²
y
+
2 ǝv/ a²v
-(rv +
1 a²
((())
ZP
ǝt
at
+
三十
ǝr Trǝe
STEADY-STATE
ар
r
Z
= 0
2P
+ +V₂
αν др
Əz
=> f f(r)
где
+
+
+
arrǝr r² 90² r² do dz²
10 dv. 1 ² ²
+ ]
32 = 41 31 (1317)
az
r Ər
r
ər
24
20
=0 => P + f (o)
BCS (1) @ra, √z=0
(2) @r=0, √z = FINITE
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