Buffers are made from weak conjugate acid-base pairs. In Part A, step 4, of the procedure a weak base, A (prepared in step 2), is mixed with a weak acid, HA (prepared in step 3), to make a buffer. In Part A, step 5, of the procedure a buffer is prepared by adding 30.0 mL of strong base NAOH to 40.0 mL of weak acid. Explain how the procedure in step 5 is able to produce a buffer. Use chemical equations (HA and A) to support your answer.

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Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Please answer question number 1 given all the steps of Part A

 

1. If boiled distilled water is not available in the laboratory, place 200 mL of distilled water in a beaker, heat
to boiling for 5 min to drive off dissolved carbon dioxide, and allow to cool. Carbon dioxide is a weak
acid that may significantly affect the results of this experiment if it is present in solution.
TIOM
2. Pipet 20.0 mL of the 0.100M acid solution into a 100 mL beaker and add 20.0 mL of 0.100 M NAOH
with a pipet. This produces 40.0 mL of 0.0500 M solution of the acid's anion, [A]=0.0500 M.
3. Pipet 20.0 mL of the 0.100 M acid solution into another 100 mL beaker and add 20.0 mL of cooled
distilled water with a pipet. This produces 40.0 mL of 0.0500 M solution of the undissociated acid, [HA]
=0.0500 M.
%3D
4. Mix the two solutions together. This produces 80.0 mL of solution in which [HA] = 0.0250 M and [A]=
0.0250 M. This solution will be referred to as buffer a.
bioe
5. Pipet 40.0 mL of 0.100 M acid solution into a 100 mL beaker. Add 10.0 mL of boiled distilled water
(cooled). Add 30.0 mL of 0.100 M NAOH solution from a buret. This will produce 80.0 mL of solution in
which the concentration of the acid's anion is about three times that of the undissociated acid. This
solution will be referred to as buffer b.
Transcribed Image Text:1. If boiled distilled water is not available in the laboratory, place 200 mL of distilled water in a beaker, heat to boiling for 5 min to drive off dissolved carbon dioxide, and allow to cool. Carbon dioxide is a weak acid that may significantly affect the results of this experiment if it is present in solution. TIOM 2. Pipet 20.0 mL of the 0.100M acid solution into a 100 mL beaker and add 20.0 mL of 0.100 M NAOH with a pipet. This produces 40.0 mL of 0.0500 M solution of the acid's anion, [A]=0.0500 M. 3. Pipet 20.0 mL of the 0.100 M acid solution into another 100 mL beaker and add 20.0 mL of cooled distilled water with a pipet. This produces 40.0 mL of 0.0500 M solution of the undissociated acid, [HA] =0.0500 M. %3D 4. Mix the two solutions together. This produces 80.0 mL of solution in which [HA] = 0.0250 M and [A]= 0.0250 M. This solution will be referred to as buffer a. bioe 5. Pipet 40.0 mL of 0.100 M acid solution into a 100 mL beaker. Add 10.0 mL of boiled distilled water (cooled). Add 30.0 mL of 0.100 M NAOH solution from a buret. This will produce 80.0 mL of solution in which the concentration of the acid's anion is about three times that of the undissociated acid. This solution will be referred to as buffer b.
1. Buffers are made from weak conjugate acid-base pairs. In Part A, step 4, of the procedure a weak base, A
(prepared in step 2), is mixed with a weak acid, HA (prepared in step 3), to make a buffer. In Part A, step 5,
of the procedure a buffer is prepared by adding 30.0 mL of strong base NaOH to 40.0 mL of weak acid.
Explain how the procedure in step 5 is able to produce a buffer. Use chemical equations (HA and A) to
support your answer.
INTRONCTION
deteris
This
Transcribed Image Text:1. Buffers are made from weak conjugate acid-base pairs. In Part A, step 4, of the procedure a weak base, A (prepared in step 2), is mixed with a weak acid, HA (prepared in step 3), to make a buffer. In Part A, step 5, of the procedure a buffer is prepared by adding 30.0 mL of strong base NaOH to 40.0 mL of weak acid. Explain how the procedure in step 5 is able to produce a buffer. Use chemical equations (HA and A) to support your answer. INTRONCTION deteris This
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