boxes move under the effect of the applied force F = 40 N. Coefficient of friction between the surfaces is 0.3. Masses m1 = 4 kg and m2 = 1.5 kg. Angle θ = 31°. Solve the acceleration of the boxes. Solve the velocity of the box after 5 sec. Solve the tension on the rope

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A: Given: M1=7 kgM2=12 kgM3=4 kgR=3 m The free-body diagram of the system is given bwlow.

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A: We can solve this problem by balancing forces on masses m1 and m2 .

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A: Given data: Inner radius, r=0.74 cm=7.4×10-3m Outer radius, R=4.1 cm=41×10-3m Mass of yo-yo, m=440…

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A: Marian pull by force F1=200 NMichael pull by force =F2θ=30°Resultant force R=420 N

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Q: Problem 2. Consider the system shown in Figure 1 with m,= 12.5 kg, m, = 20.0 kg. Object m, is…

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A: Given that m1 = 10 kg m2 = 26 kg F = 117 N angle = 21 coeff of friction = 0.136

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Q: Four Forces Force Direction 1-component y-component TNT (*) 60° 160° 260° 325 R+F F = mg g = 9.80…

A: (a). The force acting on the mass m1 is  F1=m1g=0.155×9.8=1.51 N Along x-axis,…

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A: Given: The mass of the ball is m=67.8 g. The angle of flight is θ=25.10. The horizontal range (total…

Q: Problem 3: In the figure shown, mass m1 = 10.7 kg, m2 = 10.3 kg, and the surfaces are all…

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