g=10 m/s^2 ### Physics Problem: Forces on an Inclined Plane#### Problem Statement:A block is placed on an inclined plane that makes a 30° angle with the horizontal. The gravitational force acting on the block (F_grav) is 420 N. The coefficient of friction (μ) between the block and the inclined plane is 0.20.#### Diagram:- **Inclined Plane**: A plane inclined at a 30° angle to the horizontal.- **Block**: A block on the inclined plane.- **Forces**: - **F_norm** (Normal Force): Perpendicular to the inclined plane. - **F_fric** (Frictional Force): Parallel to the inclined plane, opposing motion. - **F_grav** (Gravitational Force): Acting vertically downward.#### Parameters to Determine:- **m** (mass): __________ kg- **a** (acceleration): __________ m/s²- **ΣF** (net force): __________ N#### Equations:1. **Normal Force (F_norm)** = __________ N2. **Frictional Force (F_fric)** = __________ N3. **Mass (m)** = __________ kg4. **Acceleration (a)** = __________ m/s²5. **Net Force (ΣF)** = __________ NUse the given values and equations of motion to solve for the unknowns.> **Note**: > - The frictional force (F_fric) is given by: `F_fric = μ * F_norm`> - The normal force (F_norm) can be determined using the component of gravitational force perpendicular to the inclined plane.> - The net force (ΣF) can be determined by analyzing the forces parallel to the inclined plane.> - The acceleration can be found using Newton's second law: `ΣF = m * a`

Answered: Image /qna-images/answer/39619cfc-fd26-42aa-9313-7c850fadf309.jpg

Answered: From μ=0.20 30° m= a= Ftrict= Fra=420 N…

From μ=0.20 30° m= a= Ftrict= Fra=420 N kg m/s/s N ΣF= Fnorm (normal force) = Ffrict (force of friction) = m (mass) = kg a (acceleration) = EF (net force) = N N m/s/s N

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Chapter1: Units, Trigonometry. And Vectors

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Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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Question

g=10 m/s^2

### Physics Problem: Forces on an Inclined Plane

#### Problem Statement:
A block is placed on an inclined plane that makes a 30° angle with the horizontal. The gravitational force acting on the block (F_grav) is 420 N. The coefficient of friction (μ) between the block and the inclined plane is 0.20.

#### Diagram:
- **Inclined Plane**: A plane inclined at a 30° angle to the horizontal.
- **Block**: A block on the inclined plane.
- **Forces**:
- **F_norm** (Normal Force): Perpendicular to the inclined plane.
- **F_fric** (Frictional Force): Parallel to the inclined plane, opposing motion.
- **F_grav** (Gravitational Force): Acting vertically downward.

#### Parameters to Determine:
- **m** (mass): __________ kg
- **a** (acceleration): __________ m/s²
- **ΣF** (net force): __________ N

#### Equations:
1. **Normal Force (F_norm)** = __________ N
2. **Frictional Force (F_fric)** = __________ N
3. **Mass (m)** = __________ kg
4. **Acceleration (a)** = __________ m/s²
5. **Net Force (ΣF)** = __________ N

Use the given values and equations of motion to solve for the unknowns.

> **Note**:
> - The frictional force (F_fric) is given by: `F_fric = μ * F_norm`
> - The normal force (F_norm) can be determined using the component of gravitational force perpendicular to the inclined plane.
> - The net force (ΣF) can be determined by analyzing the forces parallel to the inclined plane.
> - The acceleration can be found using Newton's second law: `ΣF = m * a`

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