q9 An object of mass 2 kg collides with an object of mass 1 kg that is at rest, as shown in the figure. A graphof the force as a function of time that the 1 kg object exerts on the 2 kg object is shown. After thecollision, the 2 kg object has a speed of 2 m, and the 1 kg object has a speed of 8 m. A student mustdetermine the initial speed vo of the 2 kg object. Which of the following options shows the correctsubstitutions into the equation Ap = FAt so that the initial speed of the unknown object can bedetermined?(2 kg)(2 m – vo) = (8000 N)(0.00125 s), because the maximum force exerted onthe 2 kg object must be considered.(2 kg)(2 - vo)(8000 N)(0.00125 s), because the average force exerted onmSthe 2 kg object must be considered.(2 kg – 1 kg)(2 -vo)(8000 N)(0.00125 s), because the difference in massand the maximum force exerted on the 2 kg object must be considered.(2 kg – 1 kg)(2 m/s – vo) = ;(8000 N)(0.00125 s), because the difference inmass and the average force exerted on the 2 kg object must be considered. +y>+X2 kg1 kg10,00080002 6000400020000 -0.00100.00150.00200.0025t (s)

Given- Mass of object 1 (m1) = 2 Kg, Mass of object 2 (m2) = 1 Kg, As object 2 is in rest initially,…

An object of mass 2 kg collides with an object of mass 1 kg that is at rest, as shown in the figure. A graph of the force as a function of time that the 1 kg object exerts on the 2 kg object is shown. After the collision, the 2 kg object has a speed of 2 , and the 1 kg object has a speed of 8 . A student must determine the initial speed vo of the 2 kg object. Which of the following options shows the correct substitutions into the equation Ap = FAt so that the initial speed of the unknown object can be determined? (2 kg)(2 - vo) = (8000 N)(0.00125 s), because the maximum force exerted on the 2 kg object must be considered. (2 kg)(2 – vo) = ÷(8000 N)(0.00125 s), because the average force exerted on the 2 kg object must be considered. (2 kg – 1 kg)(2 -vo) = (8000 N)(0.00125 s), because the difference in mass and the maximum force exerted on the 2 kg object must be considered. (2 kg – 1 kg)(2 m/s – vo) = (8000 N)(0.00125 s), because the difference in mass and the average force exerted on the 2 kg object must be considered.

An object of mass 2 kg collides with an object of mass 1 kg that is at rest, as shown in the figure. A graph of the force as a function of time that the 1 kg object exerts on the 2 kg object is shown. After the collision, the 2 kg object has a speed of 2 , and the 1 kg object has a speed of 8 . A student must determine the initial speed vo of the 2 kg object. Which of the following options shows the correct substitutions into the equation Ap = FAt so that the initial speed of the unknown object can be determined? (2 kg)(2 - vo) = (8000 N)(0.00125 s), because the maximum force exerted on the 2 kg object must be considered. (2 kg)(2 – vo) = ÷(8000 N)(0.00125 s), because the average force exerted on the 2 kg object must be considered. (2 kg – 1 kg)(2 -vo) = (8000 N)(0.00125 s), because the difference in mass and the maximum force exerted on the 2 kg object must be considered. (2 kg – 1 kg)(2 m/s – vo) = (8000 N)(0.00125 s), because the difference in mass and the average force exerted on the 2 kg object must be considered.

College Physics

11th Edition

ISBN:9781305952300

Author:Raymond A. Serway, Chris Vuille

Publisher:Raymond A. Serway, Chris Vuille

Chapter1: Units, Trigonometry. And Vectors

Section: Chapter Questions

Problem 1CQ: Estimate the order of magnitude of the length, in meters, of each of the following; (a) a mouse, (b)...

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