A 0.251 kg particle moves in an xy plane according to x(t) = - 18.0 +2.00 t-3.00 t3 and y(t) = 22.0+ 7.00 t - 10.0 t², with x and y in meters and t in seconds. At t = 1.58 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
A 0.251 kg particle moves in an xy plane according to x(t) = - 18.0 +2.00 t-3.00 t3 and y(t) = 22.0+ 7.00 t - 10.0 t², with x and y in meters and t in seconds. At t = 1.58 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
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A 0.251 kg particle moves in an xy plane according to x(t) = - 18.0 +2.00 t - 3.00 t³ and y(t) = 22.0 + 7.00 t - 10.0 t², with x and y in
meters and t in seconds. At t = 1.58 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive
direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
(a) Number
9.47
(b) Number i 31.7
(c) Number
31.7
Units
Units
Units
N
° (degrees)
° (degrees)](/v2/_next/image?url=https%3A%2F%2Fcontent.bartleby.com%2Fqna-images%2Fquestion%2Fe5e2ee70-cbbb-4b2b-b4b4-bf2d59f101c8%2F0bde4aee-d00f-4d47-9fd5-219dcf8afc49%2Fzadrjog_processed.jpeg&w=3840&q=75)
Transcribed Image Text:Your answer is partially correct.
A 0.251 kg particle moves in an xy plane according to x(t) = - 18.0 +2.00 t - 3.00 t³ and y(t) = 22.0 + 7.00 t - 10.0 t², with x and y in
meters and t in seconds. At t = 1.58 s, what are (a) the magnitude and (b) the angle (within (-180°, 180°] interval relative to the positive
direction of the x-axis) of the net force on the particle, and (c) what is the angle of the particle's direction of travel?
(a) Number
9.47
(b) Number i 31.7
(c) Number
31.7
Units
Units
Units
N
° (degrees)
° (degrees)
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