STEEL DESIGNBOLTED CONNECTIONS6.Determine the value of P based on net area using a strengthreduction coefficient of 85%.Situation 1:For the figure shown, use P = 100 kN, L = 300mm,Si = 100 mm and S2 = 180 mm. Assume thediameter of a bolt is 25 mm.a.b.140.14 kN304.00 kN157.42 kN137.79 kNC.d.Find the value of P based on block shear in gusset platealong the weld.7.157.42 kN137.79 kNa.140.14 kNС.b.304.00 kNd.Compute the value of P based on shear in the weld if D =6mm.8.140.14 kN304.00 kN157.42 kN137.79 kNa.С.S,b.d.4S,The plate shown is connected at the top and atthe bottom using 8 mm fillet welds. Use Li = 200mm, L2 = 250 mm, L3 = 300 mm and P = 140 kN.2.Situation 4:S,3.PS,L2L3S21.Determine the maximum shear stress.a.118.24 MPaС.98.82 MPa33.95 MPad.92.80 MPaWELDED CONNECTIONSAn angle 150 x 100 x 10 mm is connected to thegusset plate as shown. The size of the weld is 8mm. Use P = 400 kN, c =35 mm and E70 electrodesSituation 2:for the welds.9.Solve the shear stress due to force alone.a.226.92 MPaс.49.50 MPab.221.46 MPad.261.95 MPa>P10.Calculate the maximum shear stress due to moment alone.a.226.92 MPa49.50 MPab.221.46 MPad.261.95 MPa11.Determine the maximum shear stress.a.226.92 MPaс.49.50 MPa2.Find the allowable shear stress in the welds.b.221.46 MPad.261.95 MPa483.0 MPaC.144.9 MPab.120.0 MPad.241.5 MPa3.Compute the total length of weld required.338.07 mm589.34 mma.С.488.07 mmb.d.292.84 mm4.Solve the length of weld required at the top of the angle.113.88 mma.38.88 mmC.b.299.19 mmd.374.19 mmSituation 3:A76x76 x 6 mm angular section shown is weldedto an 8 mm thick gusset plate. Steel is A36 with Fy= 248 MPa and Fu = 400 MPa. The electrode usedis E60 with Fu = 414 MPa. The length Li is 65 mm, L2is 125 mm, and the cross sectional area of theangle is 926 mm2.GussetPlateL2Allowable stresses:Tension on gross area, Ft = 0.60 FyTension on net area, Ft = 0.50 FuShear on net and effective area, Fv = 0.30 FuShear on welds, Fv = 0.30 Fu5.Calculate the value of P based on gross area.a.140.14 kNс.157.42 kNb.304.00 kNd.137.79 kN

Answered: Image /qna-images/answer/8b3ac84c-5506-45b0-a187-bad05ea0e539.jpg

BOLTED CONNECTIONS For the figure shown, use P = 100 kN, L = 300mm, SI = 100 mm and S2 = 180 mm. Assume the diameter of a bolt is 25 mm. Situation 1: S, S, 1. Determine the maximum shear stress. a. b. c. d. 118.24 MPa 98.82 MPa 33.95 MPa 92.80 MPa WELDED CONNECTIONS Situation 2: An angle 150 x 100 x 10 mm is connected to the gusset plate as shown. The size of the weld is 8 mm. Use P = 400 kN, c =35 mm and E70 electrodes for the welds. P. 1°

BOLTED CONNECTIONS For the figure shown, use P = 100 kN, L = 300mm, SI = 100 mm and S2 = 180 mm. Assume the diameter of a bolt is 25 mm. Situation 1: S, S, 1. Determine the maximum shear stress. a. b. c. d. 118.24 MPa 98.82 MPa 33.95 MPa 92.80 MPa WELDED CONNECTIONS Situation 2: An angle 150 x 100 x 10 mm is connected to the gusset plate as shown. The size of the weld is 8 mm. Use P = 400 kN, c =35 mm and E70 electrodes for the welds. P. 1°

Steel Design (Activate Learning with these NEW titles from Engineering!)

6th Edition

ISBN:9781337094740

Author:Segui, William T.

Publisher:Segui, William T.

Chapter1: Introduction

Section: Chapter Questions

Problem 1.5.6P: The data in Table 1.5.3 were obtained from a tensile test of a metal specimen with a rectangular...

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Question

STEEL DESIGN
BOLTED CONNECTIONS
6.
Determine the value of P based on net area using a strength
reduction coefficient of 85%.
Situation 1:
For the figure shown, use P = 100 kN, L = 300mm,
Si = 100 mm and S2 = 180 mm. Assume the
diameter of a bolt is 25 mm.
a.
b.
140.14 kN
304.00 kN
157.42 kN
137.79 kN
C.
d.
Find the value of P based on block shear in gusset plate
along the weld.
7.
157.42 kN
137.79 kN
a.
140.14 kN
С.
b.
304.00 kN
d.
Compute the value of P based on shear in the weld if D =
6mm.
8.
140.14 kN
304.00 kN
157.42 kN
137.79 kN
a.
С.
S,
b.
d.
4
S,
The plate shown is connected at the top and at
the bottom using 8 mm fillet welds. Use Li = 200
mm, L2 = 250 mm, L3 = 300 mm and P = 140 kN.
2.
Situation 4:
S,
3.
P
S,
L2
L3
S2
1.
Determine the maximum shear stress.
a.
118.24 MPa
С.
98.82 MPa
33.95 MPa
d.
92.80 MPa
WELDED CONNECTIONS
An angle 150 x 100 x 10 mm is connected to the
gusset plate as shown. The size of the weld is 8
mm. Use P = 400 kN, c =35 mm and E70 electrodes
Situation 2:
for the welds.
9.
Solve the shear stress due to force alone.
a.
226.92 MPa
с.
49.50 MPa
b.
221.46 MPa
d.
261.95 MPa
>P
10.
Calculate the maximum shear stress due to moment alone.
a.
226.92 MPa
49.50 MPa
b.
221.46 MPa
d.
261.95 MPa
11.
Determine the maximum shear stress.
a.
226.92 MPa
с.
49.50 MPa
2.
Find the allowable shear stress in the welds.
b.
221.46 MPa
d.
261.95 MPa
483.0 MPa
C.
144.9 MPa
b.
120.0 MPa
d.
241.5 MPa
3.
Compute the total length of weld required.
338.07 mm
589.34 mm
a.
С.
488.07 mm
b.
d.
292.84 mm
4.
Solve the length of weld required at the top of the angle.
113.88 mm
a.
38.88 mm
C.
b.
299.19 mm
d.
374.19 mm
Situation 3:
A76x76 x 6 mm angular section shown is welded
to an 8 mm thick gusset plate. Steel is A36 with Fy
= 248 MPa and Fu = 400 MPa. The electrode used
is E60 with Fu = 414 MPa. The length Li is 65 mm, L2
is 125 mm, and the cross sectional area of the
angle is 926 mm2.
Gusset
Plate
L2
Allowable stresses:
Tension on gross area, Ft = 0.60 Fy
Tension on net area, Ft = 0.50 Fu
Shear on net and effective area, Fv = 0.30 Fu
Shear on welds, Fv = 0.30 Fu
5.
Calculate the value of P based on gross area.
a.
140.14 kN
с.
157.42 kN
b.
304.00 kN
d.
137.79 kN

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