**Question 8: Eutectic Mixture of Bismuth and Cadmium**Bismuth and cadmium form a simple eutectic mixture like those discussed in class. Bismuth melts at 271°C and 1 bar, whereas cadmium melts at 321°C and 1 bar. The enthalpy of fusion of bismuth is 11.30 kJ/mol, and that of cadmium is 6.19 kJ/mol. A eutectic point is observed at 55.5 mol% cadmium.a. **Calculate the melting temperature of the eutectic mixture.** Assume ideal behavior.b. **Roughly sketch the phase diagram at 1 bar,** labeling the points described above for reference.c. **Sketch a cooling curve that passes through the eutectic point.****Explanation of Graphs and Diagrams:**For the phase diagram (part b), plot the temperature on the y-axis versus composition on the x-axis (in mol% of cadmium). Label the melting points of pure bismuth (271°C) and cadmium (321°C). The eutectic point should be marked at 55.5 mol% cadmium, with the corresponding eutectic temperature indicated.For the cooling curve (part c), illustrate temperature decreasing over time. The curve should show a characteristic horizontal segment at the eutectic temperature, where the mixture transitions from liquid to solid.

Melting point of Bismuth and cadmium one:- TMBi=271°C =271+273=544 K…

Bismuth and cadmium form a simple eutectic mixture like those discussed in class. Bismuth melts at 271°C and 1 bar, whereas cadmium melts at 321°C and 1 bar. The enthalpy of fusion of bismuth is 11.30 kJ/mol, and that of cadmium is 6.19 kJ/mol. A eutectic point is observed at 55.5 mol% cadmium. Calculate the melting temperature of the eutectic mixture. Assume ideal behavior. b. Roughly sketch the phase diagram at 1 bar, labeling the points described above for reference. Sketch a cooling curve that passes through the eutectic point. а. C.

Bismuth and cadmium form a simple eutectic mixture like those discussed in class. Bismuth melts at 271°C and 1 bar, whereas cadmium melts at 321°C and 1 bar. The enthalpy of fusion of bismuth is 11.30 kJ/mol, and that of cadmium is 6.19 kJ/mol. A eutectic point is observed at 55.5 mol% cadmium. Calculate the melting temperature of the eutectic mixture. Assume ideal behavior. b. Roughly sketch the phase diagram at 1 bar, labeling the points described above for reference. Sketch a cooling curve that passes through the eutectic point. а. C.

Chemistry

10th Edition

ISBN:9781305957404

Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste

Chapter1: Chemical Foundations

Section: Chapter Questions

Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...

See similar textbooks

Similar questions

Please don't provide handwritten solution
Naphthalene (C10H8) is a solid at room temperature and 100 kPa. At 100 kPa it melts at 80.2 oC. The melting point increases by 2.32 oC when the pressure is increased to 104kPa. Naphthalene boils at 219 oC, at atmospheric pressure. The vapour pressure of naphthalene at 201 oC is 67.0 kPa. The triple point of naphthalene is at 80°C and 2.1 kPa. Use this data to construct a ln(p)-T phase diagram for naphthalene and label all the regions of your diagram (you do not need to draw the diagram to scale). Please draw this diagram.
How much heat is required to change 225g of ice at 205K into liquid water at 305K? Remember that the melting point of water is 273K. A tank contains .92 moles of CO2 at a pressure of 7.1atm and a temp of 285K. What is the volume of the tank? Hi I'm having trouble figuring out these questions, and I would appreciate it if someone could explain to me how to solve them.
Give detailed Solution with explanation needed
The chlorofluorocarbon CCl2F2 (Freon; MW=120.91 g/mol) was once used as a refrigerant. Cooling comes from the evaporation of the refrigerant. Calculate the mass of CCl2F2 that must evaporate in order to freeze 15.00 g of water initially at +20.0°C. The heat of vaporization, Hvap, of CCl2F2 is 34.94kJ/mol. (Hint: It will be helpful to remember the first law of thermodynamics – Energy is conserved.)
Thank you.
The vapour pressure of a substance describes how readily molecules at the surface of the substance enter the gaseous phase. At the boiling point of a liquid, the liquid's vapour pressure is equal to or greater than the atmospheric pressure exerted on the surface of the liquid. Since the atmospheric pressure at higher elevations is lower than at sea level, the boiling point of water decreases as the elevation increases. The atmospheric pressure at sea level is 760 mmHg. This pressure decreases by 6.50 mmHg for every 100 m increase in elevation. Part A What is the boiling point of water at an elevation of 7600 m ? Express your answer with the appropriate units using three significant figures. Elevation Pressure • View Available Hint(s) 760 mmHg 1000 m 695 mmHg HA 2000 m 630 mmHg The boiling point of water decreases 0.05 °C for every 1 mmHg drop in atmospheric pressure. T = 75.30 Enter your answer using units of temperature. No credit lost. Try again.
Clausius Clapeyron for enthalpy of vaporization; might be using the graph-data wrong
What is the vapor pressure of a liquid (in mmHg) at 305.13 K if its AHvap = 28.9 kJ/mol and its normal boiling point is 341.88 K?
AH vap In(Pvap) R The following graph was obtained for a pure volatile liquid substance. In(Pvap) 4 3 2 -1 -2 -3 -4 == ²( ) + C 0.002 (Note that Pvap is the vapour pressure in atm.) 1/T (K-¹) Determine the enthalpy of vaporization for this substance. Hvap 0.003
The change in enthalpy, AH, for dissolving toluene (C,H,) in water is approximately zero. Do you predict toluene will dissolve in water? Why or why not? O Toluene will dissolve in water because LDFs and dipole-induced dipole interactions will form between them. O Toluene will dissolve in water because there are more arrangements for the toluene molecules when mixed with water. O Toluene will not dissolve in water because toluene is non-polar and water is polar. Toluene will not dissolve in water because there would be fewer arrangements for the water molecules if it were to dissolve. O O Toluene will not dissolve in water because there are no attractive forces that exist between toluene and water.
The vapour pressure of a pure substance at various temperatures is presented below. T (°C) Pvap (mmHg) 0.0 10.5 15.0 18.6 25.0 26.4 40.0 42.8 60.0 76.2 80.0 127.0 a) Calculate H°vap for this substance. b)What is the substance's normal boiling point?