5. Using the trendline on the graph, calculate the enthalpy of vaporization (AHvap) of water. ( R = 8.314 x 10* kJ/mol-K). Vapor Pressure of Water 6.20 6.00 5.80 y = -4948.2x + 19.925 5.60 5.40 5.20 5.00 4.80 4.60 4.40 0.0028 0.00285 0.0029 0.00295 0.003 0.00305 0.0031 1/T (K-1) Ln P
5. Using the trendline on the graph, calculate the enthalpy of vaporization (AHvap) of water. ( R = 8.314 x 10* kJ/mol-K). Vapor Pressure of Water 6.20 6.00 5.80 y = -4948.2x + 19.925 5.60 5.40 5.20 5.00 4.80 4.60 4.40 0.0028 0.00285 0.0029 0.00295 0.003 0.00305 0.0031 1/T (K-1) Ln P
Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
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Question
Clausius-Clapeyron equation
LnP = -deltaH vap /RT+ C
Transcribed Image Text:50
Appendix C
40-
Vapor Pressure
of Water
30
10
10
20
30
Temperature (°C)
Japor pressure of water as a function of temperature
Temperature (°C)
Pressure (Torr)
4.6
6.5
10
9.2
11
9.8
12
10.5
13
11.2
14
12.0
15
12.5
16
13.6
17
14.5
18
15.5
19
16.5
20
17.5
21
18.6
22
19.8
23
21.0
24
22.3
25
23.8
26
25.2
27
26.7
28
28.3
29
30.0
30
31.8
31
33.7
32
35.7
33
37.7
34
39.9
35
42.2
37*
47.1
100
760
*Body temperature
-44 Vapor Pressure of Water
254
Vapor Pressure (Torr)
20
Transcribed Image Text:5. Using the trendline on the graph, calculate the enthalpy of vaporization (AHvap) of water. ( R
= 8.314 x 103KJ/mol-K).
Ivap,
Vapor Pressure of Water
6.20
6.00
5.80
y = -4948.2x + 19.925
5.60
5.40
55.20
5.00
4.80
4.60
4.40
0.0028
0.00285
0.0029
0.00295
0.003
0.00305
0.0031
1/T (K-1)
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