Cellular Respiration = Theoretical Energy Glucose contains 686 to 720 kcal/mol • ATP contains 7.3 kcal/mol 36 ATP harvested from each molecule of glucose 2 from glycolysis – substrate level phosphorylation 2 from Kreb's cycle – converted from GTP (not done by all cells) 32 from the ETC & NADH/FADH2 note: NADH in the cytosol is only worth 2ATP; NADH in the mitochondria are worth 3 ATP 36 moles of ATP × 7.3 kcal/mol = 263 kcal trapped as ATP efficiency : 263/686 = 36 to 38% efficiency in converting the potential energy of glucose into chemical energy

Biochemistry
9th Edition
ISBN:9781319114671
Author:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Chapter1: Biochemistry: An Evolving Science
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

List ALL of the substrate-level phosphorylation steps in

cellular respiration and the enzymes that perform these SP steps.

For your answer, use this format:

reactant. poroduct . enzyme

 

 

 

 

Cellular Respiration = Theoretical Energy
Glucose contains 686 to 720 kcal/mol
• ATP contains 7.3 kcal/mol
36 ATP harvested from each molecule of glucose
2 from glycolysis – substrate level phosphorylation
2 from Kreb's cycle – converted from GTP (not done by all cells)
32 from the ETC & NADH/FADH2
note: NADH in the cytosol is only worth 2ATP; NADH in the mitochondria are
worth 3 ATP
36 moles of ATP × 7.3 kcal/mol = 263 kcal trapped as ATP
efficiency : 263/686 = 36 to 38% efficiency in converting the
potential energy of glucose into chemical energy
Transcribed Image Text:Cellular Respiration = Theoretical Energy Glucose contains 686 to 720 kcal/mol • ATP contains 7.3 kcal/mol 36 ATP harvested from each molecule of glucose 2 from glycolysis – substrate level phosphorylation 2 from Kreb's cycle – converted from GTP (not done by all cells) 32 from the ETC & NADH/FADH2 note: NADH in the cytosol is only worth 2ATP; NADH in the mitochondria are worth 3 ATP 36 moles of ATP × 7.3 kcal/mol = 263 kcal trapped as ATP efficiency : 263/686 = 36 to 38% efficiency in converting the potential energy of glucose into chemical energy
Expert Solution
steps

Step by step

Solved in 3 steps

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781319114671
Author:
Lubert Stryer, Jeremy M. Berg, John L. Tymoczko, Gregory J. Gatto Jr.
Publisher:
W. H. Freeman
Lehninger Principles of Biochemistry
Lehninger Principles of Biochemistry
Biochemistry
ISBN:
9781464126116
Author:
David L. Nelson, Michael M. Cox
Publisher:
W. H. Freeman
Fundamentals of Biochemistry: Life at the Molecul…
Fundamentals of Biochemistry: Life at the Molecul…
Biochemistry
ISBN:
9781118918401
Author:
Donald Voet, Judith G. Voet, Charlotte W. Pratt
Publisher:
WILEY
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781305961135
Author:
Mary K. Campbell, Shawn O. Farrell, Owen M. McDougal
Publisher:
Cengage Learning
Biochemistry
Biochemistry
Biochemistry
ISBN:
9781305577206
Author:
Reginald H. Garrett, Charles M. Grisham
Publisher:
Cengage Learning
Fundamentals of General, Organic, and Biological …
Fundamentals of General, Organic, and Biological …
Biochemistry
ISBN:
9780134015187
Author:
John E. McMurry, David S. Ballantine, Carl A. Hoeger, Virginia E. Peterson
Publisher:
PEARSON