Chemistry
10th Edition
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Chapter1: Chemical Foundations
Section: Chapter Questions
Problem 1RQ: Define and explain the differences between the following terms. a. law and theory b. theory and...
Related questions
Question
I want the best value for percent purity and how did you arrive at the best value

Transcribed Image Text:Part III-Commercial Aspirin
Trial 1
Trial 2
.371g
.381g
Mass of aspirin tablet (g)
2.06 x 10 ^-3
2.11 x 10 ^3 mol asp
Theoretical moles in tablet
Show calculations for theoretical moles:
1:.371 g asp x 1.00 mol / 180.16 g asp = 2.06 x 10 ^-3 mol
asp
2:.381 g asp x 1.00 mol / 180.16 g asp = 2.11 x 10 ^-3 mol
Molarity of NaOH (mol/L)
216
Volume of NaOH used (mL)
1:5.31 mL
2:7.31 mL
Color of Solution
1: very light pink, faded away
2: better color than 1, light pink color
Moles of NaOH used
1:115moles
2:.158 moles
Show calculations for moles NaOH:
1:216 mol NaOH/1.00 L x .531 NaOH used = .115 moles
2: .216 mol NaOH / 1.00 Lx.731 L NaOH used =.158 moles
Percent purity of aspirin (%)
65.4%
Example Calculation:
1:.246 g asp/.371 x 100 66.2 %
2:246 g asp/.381 g asp = 64.6 %
avg: .246 g asp/.376 g asp x 100 = 65.4%
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