Below is a table that shows samples of computed p values and the corresponding level of significance. _a (alpha). Put the appropriate remarks whether reject H₁ or to accept Ho. Ho is your null hypothesis. Computed p-value Interpretation Level of Significance a 10. p = 0.15 a =0.01
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- Determine the test statisticthank youThe average American gets a haircut every 43 days. Is the average larger for college students? The data below shows the results of a survey of 11 college students asking them how many days elapse between haircuts. Assume that the distribution of the population is normal. 38, 37, 38, 45, 53, 55, 35, 37, 35, 41, 38 What can be concluded at the the α = 0.05 level of significance level of significance? For this study, we should use? Select an answer: t-test for a population mean? z-test for a population mean? The null and alternative hypotheses would be: H0:H0? p or μ Select an answer > = ≠ ≤ < ≥ H1:H1? μ or p Select an answer ≠ ≥ > ≤ = < 2. The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = _______ (Please show your answer to 3 decimal places.) The p-value is? > or ≤ α 3. Based on this, we should?? Select an answer reject ? accept ? or fail to reject ?…
- I need help with this problem Conduct a hypothesis test about the mean cost per square foot at a chosen significance level. Reference an internet source for the current average (or median) cost per square foot of homes in Orange County. Discuss/explain your choice of significance level for your hypothesis test in #1 as it relates to the power of a test and Type I/II errors.A hypothesis will be used to test that a population mean equals 14 against the alternative that the population mean is less than 14 with known variance o. What is the critical value for the test statistic Zo for the significance level of 0.010? Round your answer to two decimal places (e.g. 98.76). Za = ii want to make sure
- A data set includes data from student evaluations of courses. The summary statistics aren=98, x= 3.41, s= 0.59. Use a 0.01 significance level to test the claim that the population of student course evaluations has a mean equal to 3.50. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion that addresses the original claim. ..... What are the null and alternative hypotheses? ОВ. Но и3.50 O A. Ho:u=3.50 H,:µ> 3.50 OA. Hqi H#3.50 O C. Ho: H= 3.50 H1:µ<3.50 O D. Ho: µ#3.50 H1:µ= 3.50 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. correct. V Ho. There is V evidence to conclude that the mean of the population of student course evaluations is equal to 3.50 MacBook 吕0 000 000 F7 F6 F5 F4 F3 esc F1 F2 & $ 7 8. 1 2 Y Q W E RA data set about speed dating includes "like" ratings of male dates made by the female dates. The summary statistics are n= 194, x= 5.81, s= 1.95. Use a 0.05 significance level to test the claim that the population mean of such ratings that addresses the original claim. less than 6.00. Assume that a simple random sample has been selected. Identify the null and alternative hypotheses, test statistic, P-value, and state the final conclusion What are the null and altemative hypotheses? O A. Ho: H= 6.00 O B. Ho: H 6.00 H:p#6.00 OC. Ho: H=6.00 O D. Ho: H=6.00 H: p> 6.00 Hy: H<6.00 Determine the test statistic. (Round to two decimal places as needed.) Determine the P-value. O (Round to three decimal places as needed.) State the final conclusion that addresses the original claim. V Ho. There is V evidence to conclude that the mean of the population of ratings is V 6.00. not greater than equal to Click to select your answer(s). less than étv MacBook Air FI F10 14 F7 F9 心. F6 esc F3 F2 $ % & @…The average salary for American college graduates is $48,600. You suspect that the average is less for graduates from your college. The 49 randomly selected graduates from your college had an average salary of $46,486 and a standard deviation of $9,200. What can be concluded at the αα = 0.01 level of significance? For this study, we should use Select an answer t-test for a population mean z-test for a population proportion The null and alternative hypotheses would be: H0:H0: ? p μ Select an answer = ≠ > < H1:H1: ? μ p Select an answer > ≠ = < The test statistic ? z t = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject accept fail to reject the null hypothesis. Thus, the final conclusion is that .
- 12 PM Tue Dec 14 ... ohm.lumenlearning.coma Question 7 > Test the claim that the mean GPA of night students is larger than 3.2 at the .05 significance level. The null and alternative hypothesis would be: Ho:p = 0.8 Ho:H = 3.2 Ho:u = 3.2 Ho:p = 0.8 Ho:p= 0.8 Ho:µ = 3.2 H1:p 3.2 H1:p# 0.8 H1:p> 0.8 H1:µ + 3.2 The test is: two-tailed right-tailed left-tailed Based on a sample of 45 people, the sample mean GPA was 3.21 with a standard deviation of 0.02 The test statistic is: (to 2 decimals) The critical value is: (to 2 decimals) Based on this we: O Reject the null hypothesis O Fail to reject the null hypothesis Question Help: D Post to forum Submit QuestionSalma claimed that the gas price in Blue Park neighborhood (mean of $3.65) is higher than that in Green Spring (mean of $3.59). She obtained the t-value of 2.223 after calculating data from 6 gas stations in Blue Park and 5 gas stations in Green Spring. Use the chart below and determine if Salma's claim is supported! Table 10-3. Critical values of "t" significance level p= 0.05 significance level p= 0.01 TP 1 12.706 63.657 2 4.303 9.925 3 3.182 5.841 2.776 4.604 5 2.571 4.032 6 2.447 3.707 7 2.365 3.499 2.306 3.355 9 2.262 3.250 10 2.228 3.169 11 2.201 3.106 Copy the following into your text box, fill in the blanks, and answer the questions A. The degree of freedom is: B. The t-calculated value is: and the t-critical value is : C. Comparison: t-calc t-crit (answer with ()) D. Is the null hypothesis accepted or rejected? Explain how you determined that! Also, explain what it means to reject or accept the hypothesis! E. Explain if Salma's claim is supported based on your t-value…Help please!