Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001

Introductory Circuit Analysis (13th Edition)
13th Edition
ISBN:9780133923605
Author:Robert L. Boylestad
Publisher:Robert L. Boylestad
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please solve this 3 questions
Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the
memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a
bit wise inversion function.
%10.0
"TAG_IN"
H H
OR
Byte
INV
Byte
EN
ENO
EN
ENO H
%MBO
%MB2
%MB2
"TAG VALUE1" IN1
OUT "TAG_RESULT
"TAG RESULTIN
%MB8
"TAG_RESULT
%MB1
OUT-XNOR
"TAG_VALUE2"
IN2
O a. 1010'1010
O b. 1011'0100
○ c. 0001'1000
○ d. 0000'0001
Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the
memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled?
%10.0
"TAG_IN"
OR
Byte
INV
Byte
EN
ENO
EN
ENO H
%MBO
%MB2
"TAG VALUE1" IN1
OUT TAG RESULT
%MB2
"TAG_RESULTIN
%MB8
"TAG_RESULT
OUT-XNOR"
%MB1
"TAG_VALUE2"
IN2
a. None of the choices
O b. 1011'0100
○ c. 1010'1010
O d. 1111'1110
O e. 0001'1000
Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the
memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled?
%10.0
"TAG_IN"
OR
Byte
INV
Byte
EN
ENO
EN
ΕΝΟ
%MBO
"TAG_VALUE1"
%MB2
%MB2
%MB8
IN1
OUT "TAG RESULT
"TAG RESULTIN
"TAG_RESULT
OUT-XNOR"
%MB1
"TAG_VALUE2"
IN2
Oa. None of the choices
O b. 0001'1000
O c. 1011'0100
O d. 1010'1010
O e. 0000'0001
Transcribed Image Text:Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? Hint: the INV function is a bit wise inversion function. %10.0 "TAG_IN" H H OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 %MB2 "TAG VALUE1" IN1 OUT "TAG_RESULT "TAG RESULTIN %MB8 "TAG_RESULT %MB1 OUT-XNOR "TAG_VALUE2" IN2 O a. 1010'1010 O b. 1011'0100 ○ c. 0001'1000 ○ d. 0000'0001 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ENO H %MBO %MB2 "TAG VALUE1" IN1 OUT TAG RESULT %MB2 "TAG_RESULTIN %MB8 "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 a. None of the choices O b. 1011'0100 ○ c. 1010'1010 O d. 1111'1110 O e. 0001'1000 Before the start of the PLC code including the functions below, the content of the memory byte MB8 was "1011'0100". If the content of the memory byte MBO is "1010'1010", and MB1 is "0001'1000", what will be the content of MB8 if input 10.0 is enabled? %10.0 "TAG_IN" OR Byte INV Byte EN ENO EN ΕΝΟ %MBO "TAG_VALUE1" %MB2 %MB2 %MB8 IN1 OUT "TAG RESULT "TAG RESULTIN "TAG_RESULT OUT-XNOR" %MB1 "TAG_VALUE2" IN2 Oa. None of the choices O b. 0001'1000 O c. 1011'0100 O d. 1010'1010 O e. 0000'0001
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