Because of tourism in the state, it was proposedthat public schools in Michigan begin after Labor Day. Todetermine whether support for this change was greaterthan 65%, a public poll was taken. Let p equal the pro-portion of Michigan adults who favor a post-Labor Daystart. We shall test Ho: p = 0.65 against H₁: p > 0.65.(a) Define a test statistic and an α = 0.025 critical region.(b) Given that 414 out of a sample of 600 favor a post-Labor Day start, calculate the value of the test statis-tic.(c) Find the p-value and state your conclusion.

The objective of this question is to conduct a hypothesis test to determine if the proportion of…

Answered: Because of tourism in the state, it was…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

Section: Chapter Questions

Problem 1P

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A severe storm has an average peak wave beight of 16,4 feet for waves hitting the shore. Suppose that a storm is in progress with a severe storm class rating. Let us say that we want to set up a statistical test to see if the wave action (i.e., height) is dying down or getting worse. If you wanted to test the hypothesis that the waves are dying down, what would you use for the alternate hypothesis? Is the P-value area on the left, right, or on both sides of the mean? O H:a is less than 16.4 feet; the P-value area is on the left of the mean O H:u is less than 16.4 feet; the P-value area is on the right of the mean O H: u is greater than 16.4 feet; the P-value area is on the right of the mean OH:u is not equal to 16.4 feet: the P-value area is on the left of the mean OH : u is not cqual to 16.4 feet; the P-value area is on the right of the mean
An accountant is studying how much American families donate each year to charity. The accountant states the average yearly amount donated to charity by American families is different than 5.5 thousand dollars. If we would like to test the accountant's claim with a hypothesis test using a significance level of α=0.01 , what is the rejection region? Use the graph below to show the rejection region. First, move the blue dot to choose the appropriate test (left-, right, or two- tailed). Then, slide the shaded region(s) to represent the rejection region.
A manufacturing company wants to see if there is a significant difference in three types of plastic for a new product. They randomly sample prices for each of the three types of plastic and run an ANOVA. Use α = 0.05 to see if there is a statistically significant difference in the mean prices. Part of the computer output is shown below, fill in the missing information. Use alpha= 0.01. a. Compute the test statistic. Fill out the entire ANOVA table. Round answers to at least 4 decimal places. Sample Mean Sample Size High-Density Polythene 38.5673 11 Low-Density Polythene 38.0473 15 Polyethylene Terephthalate 35.8375 8 Source S.S. df M.S. F Treatment Incorrect Correct Incorrect Incorrect Error Incorrect Correct 6.69797 Total 245.471038 Correct b. What is the critical value? Incorrect c. What is the correct decision?
a. Find the t values that form the boundaries of the critical region for a two-tailed test with ? = .05 for a sample size of n = 12. b. Repeat the above for a one-tailed test, with ? = .05.
14% of all Americans suffer from sleep apnea. A researcher suspects that a lower percentage of those who live in the inner city have sleep apnea. Of the 359 people from the inner city surveyed, 43 of them suffered from sleep apnea. What can be concluded at the level of significance of αα = 0.05? For this study, we should use Select an answer z-test for a population proportion t-test for a population mean The null and alternative hypotheses would be: Ho: ? μ p Select an answer = ≠ > < (please enter a decimal) H1: ? p μ Select an answer < > = ≠ (Please enter a decimal) The test statistic ? t z = (please show your answer to 3 decimal places.) The p-value = (Please show your answer to 4 decimal places.) The p-value is ? > ≤ αα Based on this, we should Select an answer reject fail to reject accept the null hypothesis. Thus, the final conclusion is that ... The data suggest the populaton proportion is significantly smaller than 14% at αα = 0.05, so…
Approximately 58% of all people are able to wink with both eyes. Is this percent different for people who wear glasses? A researcher tests 319 people who wear glasses and found that 204 could wink with both eyes. What can be concluded at the αα = 0.05 level of significance? For this study, we should use Select an answer z-test for the difference between two population proportions t-test for a population mean z-test for a population proportion t-test for the difference between two dependent population means t-test for the difference between two independent population means The null and alternative hypotheses would be: H0:H0: Select an answer μd p1 p μ1 μ Select an answer ≥ = ≠ ≤ H1:H1: Select an answer μ μ1 p p1 μd Select an answer < ≠ > = The test statistic ? z t = (round to 3 decimal places) The p-value = (round to 4 decimal places) The p-value is ? > ≤ αα. Based on this, we should Select an answer accept reject fail to reject the null hypothesis. Explain…
If the test requires that the results be statistically significant at a level of α = 0.05, fill in the blanks and complete the sentences that explain the test decision and conclusion. The decision is to reject the null hypothesis. There is enough evidence at a significance level of a = 0.05 that the mean weight for U.S. women of age 40-49 who smoke daily is less than 169.976 pounds.
Polyunsaturated fatty acids in the diet favorably affect several risk factors for cardiovascular disease. The principal dietary polyunsaturated fat is linoleic acid. Suppose we randomly selected twelve adults for our study. We took their blood pressure measurements (systolic blood pressure) at the start and recorded them for each adult. Then we placed required these adults to consume 23g/day of safflower oil which is high in linoleic acid for four weeks. At the end of the four weeks, we took another systolic blood pressure(SBP) measurement. The paired data is provided below: Subject 1 2 3 4 5 6 7 8 9 10 11 12 Baseline SBP 119.67 100.00 123.56 109.89 96.22 133.33 115.78 126.39 122.78 117.44 111.33 92.39 1-month SBP 117.33 98.78 123.83 107.67 95.67 128.89 113.22 121.56 126.33 110.39 107.00 93.06 Use the appropriate nonparametric test at alpha level of 0.05, to test whether the diet heavy in linoleic acid increases systolic blood pressure (SBP). Use Steps 0-5
Please answer the incorrect ones only.
It is hypothesized that 40% of the youth in a city are favour of lower legal drinking age. Out of 500 youth interviewed, 210 are in favour. Is there a significant difference between the youth who favour lower legal drinking age from the 40%? Use the z-test on any value of a population proportion and 0.01 level of significance and the critical value of +/-2.33.
A quality control expert at a local dairy claims that its cartoons contain more than 64oz of milk a sample of 15 cartoons reveals a mean of 65 and 1.1 oxs respectively. At the 1% level, does the appropriate hypothesis support his claim? find and interpret the p value
Dr. Maddan's eye drops are supposed to cause significant reduction is eye redness. The following table shows the results of a recent study where a random sample of individuals took part in a placebo controlled study. No Reduction in Redness Reduction in Redness Total Eye Drops 120 220 340 No Eye Drops Total 120 140 260 240 360 600 With 5% level of significance, determine if eye redness reduction is dependent upon taking the eye drops. Provide, a. the Chi-square statistic. b. the critical value or the p-value. c. Your decision on whether or not to reject Ho.

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