HW 11 #3 need help in part 4 should be in the second screenshot ### Part 3:This section illustrates a chemical reaction. - **Left image:** Displays a molecular structure with an arrow pointing from a bromine ion (Br⁻) to another part of the molecule, indicating a reaction process or movement of electrons.- **Right image:** Shows the resulting molecular structure after the reaction, where bromine (Br) is now part of the carbon chain.Both structures have a button labeled "view structure" to interact with the diagrams.---### Part 4 out of 5:This section depicts another chemical reaction process.- **Left image:** Shows a molecular structure including a double bond in the carbon chain and a separate molecule of hydrogen bromide (HBr).- **Right image:** Displays the resulting molecule, where the bromine has become an integral part of the structure, indicated by a positive charge on the central carbon atom. The structures are accompanied by an option to "edit structure."Next to the diagrams, there is a multiple-choice list with four options:- ○ Br⁺- ● Br⁻ (This option is selected)- ○ HBr- ○ OH⁻The "+" signifies the presence of a byproduct or an additional entity in the reaction. **Title: Understanding Reaction Mechanisms with HBr****Introduction:**In this exercise, we explore the reaction of an alkyne with excess HBr to produce two major products. Our task is to identify the second product and illustrate the stepwise mechanism for forming the first product.**Part 1: Reaction and Products**- **Reactants and Conditions:** The reaction involves an alkyne treated with excess hydrogen bromide (HBr).- **Products:** Two dibromoalkanes are formed. The structure of the second product is a dibromo compound with the bromine atoms on adjacent carbon atoms.**Part 2: Stepwise Mechanism for the First Product**- **Initial Step:** The alkyne undergoes electrophilic addition. A bromine ion (Br⁻) is one of the intermediates formed.- **Mechanism Images:** Diagrams illustrate the movement of electrons from the alkyne to the Brδ+, leading to the formation of a carbocation and subsequent bond formation with the bromide ion.**Part 3: Continuation of the Mechanism**- **Second Addition:** The next step involves the reaction of the formed bromo-alkene with another HBr molecule.- **Final Product Formation:** The final structure showcases complete addition, with Br atoms on the same carbon chain.**Conclusion:**This exercise emphasizes understanding mechanism steps and predicting organic reaction products. By following these steps, we gain insights into how alkenes react with hydrogen halides, specifically leading to addition reactions.

In the fourth and fifth step of the reaction another hydrogen bromide molecule is added to the alkene to form dibromoalkane.In the first step of the reaction a proton adds to the double bond to form a more stable carbocation intermediate:In next step of the reaction a bromide ion adds to the above formed carbocation intermediate:The mechanism of part 4 is as follows: