Based on a sample of n=24, the least-squares method was used to develop the prediction line Y, = 8+2X,. In addition, Syy = 1.2, X=9, and E (X -X)2 = 24. Complete parts (a) through (c) below. i=1 a. Construct a 90% confidence interval estimate of the population mean response for X= 4. OSHyx =40 (Round to two decimal places as needed.) b. Construct a 90% prediction interval of an individual response for X= 4. (Round to two decimal places as needed.) c. Compare the results of (a) and (b) with those for X= 9, which are 25.58 sHyix = gS 26.42 and 23.90 sYx-9s28.10. Which intervals are wider? Why? The intervals for X= V are wider because X 9 is the mean X.

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Based on a sample of n = 24, the least-squares method was used to develop the prediction line Y; = 8 + 2X;. In addition, Syx = 1.2, X= 9, and 2 (X; -X)²=24. Complete parts (a) through (c) below.
i= 1
a. Construct a 90% confidence interval estimate of the population mean response for X= 4.
|<HY)X=4
(Round to two decimal places as needed.)
b. Construct a 90% prediction interval of an individual response for X = 4.
IsYx=4
(Round to two decimal places as needed.)
c. Compare the results of (a) and (b) with those for X = 9, which are 25.58 < Hyi 9s26.42 and 23.90 <Yx=9< 28.10. Which intervals are wider? Why?
= 9
= 9
The intervals for X=
are wider because X= 9 is
the mean X.
Transcribed Image Text:n Based on a sample of n = 24, the least-squares method was used to develop the prediction line Y; = 8 + 2X;. In addition, Syx = 1.2, X= 9, and 2 (X; -X)²=24. Complete parts (a) through (c) below. i= 1 a. Construct a 90% confidence interval estimate of the population mean response for X= 4. |<HY)X=4 (Round to two decimal places as needed.) b. Construct a 90% prediction interval of an individual response for X = 4. IsYx=4 (Round to two decimal places as needed.) c. Compare the results of (a) and (b) with those for X = 9, which are 25.58 < Hyi 9s26.42 and 23.90 <Yx=9< 28.10. Which intervals are wider? Why? = 9 = 9 The intervals for X= are wider because X= 9 is the mean X.
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