4.2.3 4.2.4 What is a 95% prediction interval for the chest girth of a bear with a neck girth of 20 inches? The standard error of the fit, s.e.(fit), = 0.880 a. (27.9, 43.9) b. (28.1, 43.7) c. (34.1, 37.8) d. None of the above Interpret the prediction interval obtained in 4.2.3

MATLAB: An Introduction with Applications
6th Edition
ISBN:9781119256830
Author:Amos Gilat
Publisher:Amos Gilat
Chapter1: Starting With Matlab
Section: Chapter Questions
Problem 1P
icon
Related questions
Question

Answer Question 4.2.3 and 4.2.4

4.2
A sample of 19 female bears was measured for chest girth (y) and neck girth (x), both in
inches. The least squares regression equation relating the two variables is = 5.32 + 1.53 x.
The standard deviation of the regression is s = 3.692. y^
4.2.1 What is a 95% confidence interval for the average (or mean) chest girth for bears with
a neck girth of 20 inches? The standard error of the fit is s.e.(fit) = 0.880
a. (27.9, 43.9)
4.2.2
4.2.3
4.2.4
b. (28.1, 43.7)
c. (34.1, 37.8)
d. None of the above
Interpret the confidence interval obtained in 4.2.1
What is a 95% prediction interval for the chest girth of a bear with a neck girth of 20
inches? The standard error of the fit, s.e.(fit), = 0.880
a. (27.9, 43.9)
b. (28.1, 43.7)
c. (34.1, 37.8)
d. None of the above
Interpret the prediction interval obtained in 4.2.3
Transcribed Image Text:4.2 A sample of 19 female bears was measured for chest girth (y) and neck girth (x), both in inches. The least squares regression equation relating the two variables is = 5.32 + 1.53 x. The standard deviation of the regression is s = 3.692. y^ 4.2.1 What is a 95% confidence interval for the average (or mean) chest girth for bears with a neck girth of 20 inches? The standard error of the fit is s.e.(fit) = 0.880 a. (27.9, 43.9) 4.2.2 4.2.3 4.2.4 b. (28.1, 43.7) c. (34.1, 37.8) d. None of the above Interpret the confidence interval obtained in 4.2.1 What is a 95% prediction interval for the chest girth of a bear with a neck girth of 20 inches? The standard error of the fit, s.e.(fit), = 0.880 a. (27.9, 43.9) b. (28.1, 43.7) c. (34.1, 37.8) d. None of the above Interpret the prediction interval obtained in 4.2.3
Expert Solution
trending now

Trending now

This is a popular solution!

steps

Step by step

Solved in 3 steps with 1 images

Blurred answer
Similar questions
  • SEE MORE QUESTIONS
Recommended textbooks for you
MATLAB: An Introduction with Applications
MATLAB: An Introduction with Applications
Statistics
ISBN:
9781119256830
Author:
Amos Gilat
Publisher:
John Wiley & Sons Inc
Probability and Statistics for Engineering and th…
Probability and Statistics for Engineering and th…
Statistics
ISBN:
9781305251809
Author:
Jay L. Devore
Publisher:
Cengage Learning
Statistics for The Behavioral Sciences (MindTap C…
Statistics for The Behavioral Sciences (MindTap C…
Statistics
ISBN:
9781305504912
Author:
Frederick J Gravetter, Larry B. Wallnau
Publisher:
Cengage Learning
Elementary Statistics: Picturing the World (7th E…
Elementary Statistics: Picturing the World (7th E…
Statistics
ISBN:
9780134683416
Author:
Ron Larson, Betsy Farber
Publisher:
PEARSON
The Basic Practice of Statistics
The Basic Practice of Statistics
Statistics
ISBN:
9781319042578
Author:
David S. Moore, William I. Notz, Michael A. Fligner
Publisher:
W. H. Freeman
Introduction to the Practice of Statistics
Introduction to the Practice of Statistics
Statistics
ISBN:
9781319013387
Author:
David S. Moore, George P. McCabe, Bruce A. Craig
Publisher:
W. H. Freeman