Answer Question 4.2.3 and 4.2.4 4.2A sample of 19 female bears was measured for chest girth (y) and neck girth (x), both ininches. The least squares regression equation relating the two variables is = 5.32 + 1.53 x.The standard deviation of the regression is s = 3.692. y^4.2.1 What is a 95% confidence interval for the average (or mean) chest girth for bears witha neck girth of 20 inches? The standard error of the fit is s.e.(fit) = 0.880a. (27.9, 43.9)4.2.24.2.34.2.4b. (28.1, 43.7)c. (34.1, 37.8)d. None of the aboveInterpret the confidence interval obtained in 4.2.1What is a 95% prediction interval for the chest girth of a bear with a neck girth of 20inches? The standard error of the fit, s.e.(fit), = 0.880a. (27.9, 43.9)b. (28.1, 43.7)c. (34.1, 37.8)d. None of the aboveInterpret the prediction interval obtained in 4.2.3

Given that Sample size n =19 Regression equation Y^ =5.32 + 1.53x Standard error of the fit=0.880…

Answered: 4.2.3 4.2.4 What is a 95% prediction…

MATLAB: An Introduction with Applications

6th Edition

ISBN:9781119256830

Author:Amos Gilat

Publisher:Amos Gilat

Chapter1: Starting With Matlab

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4.2.3 4.2.4 What is a 95% prediction interval for the chest girth of a bear with a neck girth of 20 inches? The standard error of the fit, s.e.(fit), = 0.880 a. (27.9, 43.9) b. (28.1, 43.7) c. (34.1, 37.8) d. None of the above Interpret the prediction interval obtained in 4.2.3