Based on a sample of n= 23, the least-squares method was used to develop the prediction line Y, = 8+ 3X,. In addition, Syy = 3.8, X= 6, and > (x -X)2 = 23. Complete parts (a) and (b) below. i=1 Click here for page 1 of critical values of t. Click here for page 2 of critical values of t. a. Construct a 90% confidence interval estimate of the population mean response for X = 4. (Round to four decimal places as needed.) b. Construct a 90% prediction interval of an individual response for X= 4. (Round to four decimal places as needed.)

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Based on a sample of n = 23, the least-squares method was used to develop the prediction line Y; = 8 + 3X;. In addition, Syx = 3.8, X= 6, and 2 (X; - X) = 23. Complete parts (a) and (b) below.
i= 1
Click here for page 1 of critical values of t. Click here for page 2 of critical values of t.
a. Construct a 90% confidence interval estimate of the population mean response for X= 4.
O< HYIX = 43
(Round to four decimal places as needed.)
b. Construct a 90% prediction interval of an individual response for X= 4.
SYx=45
(Round to four decimal places as needed.)
Transcribed Image Text:Based on a sample of n = 23, the least-squares method was used to develop the prediction line Y; = 8 + 3X;. In addition, Syx = 3.8, X= 6, and 2 (X; - X) = 23. Complete parts (a) and (b) below. i= 1 Click here for page 1 of critical values of t. Click here for page 2 of critical values of t. a. Construct a 90% confidence interval estimate of the population mean response for X= 4. O< HYIX = 43 (Round to four decimal places as needed.) b. Construct a 90% prediction interval of an individual response for X= 4. SYx=45 (Round to four decimal places as needed.)
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