based off the image: calculate the value of the test statistic for the appropriate hypothesis test.
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Q: Illustrate the null hypothesis for a correlated t test?
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Q: (ou wish to test the following claim (Ha) at a significance level of a = 0.01. H.:P1 = P2 Ha:P1 > P2…
A: Gfygsdb
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Q: Use the technology display, which results from the head injury measurements from car crash dummies…
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A: Given: α=0.1
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- You wish to test the following claim (Ha) at a significance level of a = 0.01. H.:P1 = P2 Ha:P1 > P2 The 1st population's sample has 74 successes and a sample size = 371. The 2nd population's sample has 47 successes and a sample size = 396. What is the test statistic (z-score) for this sample? (Round to 3 decimal places.) test statistic = What is the p-value for this sample? (Round to 3 decimal places.) p-value = The p-value is... O less than (or equal to) a greater than a This test statistic leads to a decision to... reject the null O fail to reject the null accept the null As such, the final conclusion is that... O The sample data support the alternate hypothesis claim that p1 > p2. O There is not sufficient sample evidence to support the alternate hypothesis claim that p1 > p2.Thumbs-up is a popular and new soft drink company in India. The company wants to test the market for its product. A sample of 500 individuals participated in the taste test and 125 indicated that they like the taste. We would like to test if more than 20% of the population will like the new soft drink. For alpha=95% confidence, test the hypothesis.A health manager wants to assess the relationship between number of doctor visits and patient feedbacks.Patient feedbacks are categorized between 1= very bad and 5= very goodin a scale. The SPSS analysis is given below. Write down the hypothesis for this case and specify the test used and comment on the results. Patient Feedback Visit to Doctor 5.00 2.00 4.00 1.00 4.00 2.00 5.00 3.00 4.00 3.00 3.00 4.00 3.00 4.00 4.00 4.00 2.00 5.00 2.00 5.00 3.00 5.00 1.00 4.00 One-Sample Kolmogorov-Smirnov Test Kisisel Saglik Degerlendirmesi Gecen Yil Icindeki Hekim Ziyaret Sayisi N 12 12 Normal Parametersa,b Mean 3.3333 3.5000 Std. Deviation 1.23091 1.31426 Most Extreme Differences Absolute .206 .232 Positive .127 .127 Negative -.206 -.232 Kolmogorov-Smirnov Z .713 .802 Asymp. Sig. (2-tailed) .689 .541 a. Test…
- Test the claim that the proportion of people who own cats is smaller than 60% at the 0.025 significance level. The null and alternative hypothesis would be: Ho: p=0.6 Ho:μ ≥ 0.6 Ho: p 0.6 The test is: left-tailed right-tailed two-tailed Based on a sample of 600 people, 53% owned cats The test statistic is: The p-value is: Based on this we: Ho:p>0.6 Ho: 0.6 Ho: μ 0.6 Reject the null hypothesis O Fail to reject the null hypothesis (to 2 decimals) (to 2 decimals) =You wish to test the following claim (H) at a significance level of a = Ho: P1 = P2 Ha: P₁ P2 You obtain a sample from the first population with 122 successes and 438 failures. You obtain a sample from the second population with 63 successes and 304 failures. test statistic = p-value = [three decimal accuracy] 0.001. [four decimal accuracy]Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.01 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? Click the icon to view the data table and technology display. What are the null and alternative hypotheses? O A. Ho: Head injury measurements are affected by an interaction between type of car and size of B. Ho: Head injury measurements are not affected by an interaction between type of car and size of the car. H₁: Head injury measurements are affected by an interaction between type of car and size of the car. the car. H₁: Head injury measurements are not affected by an interaction between type of car and size…
- Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.10 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? Click the icon to view the data table and technology display. What are the null and alternative hypotheses? O A. Ho: Head injury measurements are not affected by an interaction between type of car and size of the car. H₁: Head injury measurements are affected by an interaction between type of car and size of the car. O C. Ho: Head injury measurements are not affected by type of car. H₁: Head injury measurements are affected by type of car. Find the test statistic. F = (Round to two decimal places as needed.)…When would you use a one-way ANOVA test rather than an independent sample t-test?Use the technology display, which results from the head injury measurements from car crash dummies listed below. The measurements are in hic (head injury criterion) units, and they are from the same cars used for the table below. Use a 0.10 significance level to test the given claim. Test the null hypothesis that head injury measurements are not affected by an interaction between the type of car (foreign, domestic) and size of the car (small, medium, large). What do you conclude? A. F = 1.41, p-value = 0.281 B. F = 2.25, p-value = 0.159 C. F = 1.37, p-value = 0.290 D. F = 0.44, p-value = 0.655
- (c) Calculate the test statistic. d) Decide whether to reject or fail to reject the null hypothesis. Then interpret the decision in the context of the original claim.A recent study investigated if the distribution of gender is the same across all academic ranks. Data were collected by taking a random sample of individuals from within each academic rank and then recording each individuals gender. Use the output below to conduct the appropriate hypothesis test. Use a 0.05 level of significance. Null and alternative hypotheses Test Statistic value p-value decision based on the p-valueANOVA is another kind of hypothesis testing. Did reading this section increase the understanding of hypothesis testing? How is an F-stat different from or similar to a z-score? Why are the hypothesis statements written differently for ANOVA than from the z-test?