base is 1 m and its height is 1 m. If we fill the cube with water, we can say we have 1 m of water per unit area. Darcy's law can be rearranged to calculate the volume flow rate per unit area. This is called the specific discharge, which has units of length per time (for example, meters per day, m/day). Completing parts (a) through (c) will illustrate how specific discharge is related to the volume flow rate. (Hint: Assume that the units for hydraulic con- -the cross-sectional area of the cube- ductivity are m/day and the units for cross-sectional m².) area are m' (a) Suppose 1 m’ of water is pumped from a well into an empty cylindrical tank. If the water level is 2 m above the base, what is the cross-sectional area of the tank? (Hint: Volume of a cylinder = rh = area of base X height.) (b) If it takes half a day to pump the 1 m’ of water into the tank, what is the flow rate in terms of both vol- ume per unit time and specific discharge? (c) Write Darcy's law so that it calculates the specific discharge.

base is 1 m and its height is 1 m. If we fill the cube with water, we can say we have 1 m of water per unit area. Darcy's law can be rearranged to calculate the volume flow rate per unit area. This is called the specific discharge, which has units of length per time (for example, meters per day, m/day). Completing parts (a) through (c) will illustrate how specific discharge is related to the volume flow rate. (Hint: Assume that the units for hydraulic con- -the cross-sectional area of the cube- ductivity are m/day and the units for cross-sectional m².) area are m' (a) Suppose 1 m’ of water is pumped from a well into an empty cylindrical tank. If the water level is 2 m above the base, what is the cross-sectional area of the tank? (Hint: Volume of a cylinder = rh = area of base X height.) (b) If it takes half a day to pump the 1 m’ of water into the tank, what is the flow rate in terms of both vol- ume per unit time and specific discharge? (c) Write Darcy's law so that it calculates the specific discharge.

Structural Analysis

6th Edition

ISBN:9781337630931

Author:KASSIMALI, Aslam.

Publisher:KASSIMALI, Aslam.

Chapter2: Loads On Structures

Section: Chapter Questions

Problem 1P

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Basic Terminologies

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Common Units Of Pressure

Pressure is something that we experience in daily life but fail to recognize it as our body is so accustomed to it. For example, the atmospheric air applies pressure on our body, but we don’t feel it as we are exposed to it since birth and our body is habitual to it. When we write using a pen, we need to apply some pressure over the pen to make it start writing. But these are our day-to-day activity which we fail to recognize

Question

36. Darcy's law gives us the volume flow rate-volume per
time (for example, cubic meters per day, m³/day).
Another way to express volume is on a per-unit-area
basis. For example, if we have a 1-m’ cube, we know its
3
3

2
base is 1 m -the cross-sectional area of the cube-
and its height is 1 m. If we fill the cube with water, we
can say we have 1 m of water per unit area. Darcy's law
can be rearranged to calculate the volume flow rate per
unit area. This is called the specific discharge, which has
units of length per time (for example, meters per day,
m/day). Completing parts (a) through (c) will illustrate
how specific discharge is related to the volume flow
rate. (Hint: Assume that the units for hydraulic con-
ductivity are m/day and the units for cross-sectional
area are m².)
(a) Suppose 1 m’ of water is pumped from a well into an
empty cylindrical tank. If the water level is 2 m
above the base, what is the cross-sectional area of
the tank? (Hint: Volume of a cylinder = 7p²h =
area of base X height.)
3
= TT r
3
(b) If it takes half a day to pump the 1 m’ of water into
the tank, what is the flow rate in terms of both vol-
ume per unit time and specific discharge?
(c) Write Darcy's law so that it calculates the specific
discharge.

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