Balance this nuclear reaction by supplying the missing nucleus. Replace each question mark with an appropriate integer or symbol. 2Cf + 260 Db + 4,n 105

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**Balancing Nuclear Reactions:**

**Objective:** Balance this nuclear reaction by supplying the missing nucleus. Replace each question mark with an appropriate integer or symbol.

__Reaction:__
\[ \prescript{249}{98}{\text{Cf}} + \boxed{\begin{array}{c} ? \\ ? \end{array}} \rightarrow \prescript{260}{105}{\text{Db}} + 4 \prescript{1}{0}{\text{n}} \]

### Explanation

In this nuclear reaction, Californium-249 (\( \prescript{249}{98}{\text{Cf}} \)) reacts with an unknown nucleus to produce Dubnium-260 (\( \prescript{260}{105}{\text{Db}} \)) and 4 neutrons.

### Steps to Balance the Reaction:

1. **Identify the mass numbers and atomic numbers:**
   - Californium (Cf) has an atomic number of 98 and a mass number of 249.
   - Dubnium (Db) has an atomic number of 105 and a mass number of 260.
   - A neutron (n) has an atomic number of 0 and a mass number of 1.

2. **Set up the equation to conserve mass and atomic numbers separately:**

   For mass numbers:
   \[
   249 + A = 260 + 4 \times 1
   \]
   \[
   249 + A = 264
   \]
   \[
   A = 15
   \]

   For atomic numbers:
   \[
   98 + Z = 105 + 4 \times 0
   \]
   \[
   98 + Z = 105
   \]
   \[
   Z = 7
   \]

3. **Identify the element with atomic number 7:**
   - The element with atomic number 7 is Nitrogen (N).

### Final Balanced Reaction:
\[ \prescript{249}{98}{\text{Cf}} + \prescript{15}{7}{\text{N}} \rightarrow \prescript{260}{105}{\text{Db}} + 4 \prescript{1}{0}{\text{n}} \]

This reaction involves Californium-249 and Nitrogen-15 producing Dubnium-260 and 4 neutrons.
Transcribed Image Text:**Balancing Nuclear Reactions:** **Objective:** Balance this nuclear reaction by supplying the missing nucleus. Replace each question mark with an appropriate integer or symbol. __Reaction:__ \[ \prescript{249}{98}{\text{Cf}} + \boxed{\begin{array}{c} ? \\ ? \end{array}} \rightarrow \prescript{260}{105}{\text{Db}} + 4 \prescript{1}{0}{\text{n}} \] ### Explanation In this nuclear reaction, Californium-249 (\( \prescript{249}{98}{\text{Cf}} \)) reacts with an unknown nucleus to produce Dubnium-260 (\( \prescript{260}{105}{\text{Db}} \)) and 4 neutrons. ### Steps to Balance the Reaction: 1. **Identify the mass numbers and atomic numbers:** - Californium (Cf) has an atomic number of 98 and a mass number of 249. - Dubnium (Db) has an atomic number of 105 and a mass number of 260. - A neutron (n) has an atomic number of 0 and a mass number of 1. 2. **Set up the equation to conserve mass and atomic numbers separately:** For mass numbers: \[ 249 + A = 260 + 4 \times 1 \] \[ 249 + A = 264 \] \[ A = 15 \] For atomic numbers: \[ 98 + Z = 105 + 4 \times 0 \] \[ 98 + Z = 105 \] \[ Z = 7 \] 3. **Identify the element with atomic number 7:** - The element with atomic number 7 is Nitrogen (N). ### Final Balanced Reaction: \[ \prescript{249}{98}{\text{Cf}} + \prescript{15}{7}{\text{N}} \rightarrow \prescript{260}{105}{\text{Db}} + 4 \prescript{1}{0}{\text{n}} \] This reaction involves Californium-249 and Nitrogen-15 producing Dubnium-260 and 4 neutrons.
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