Identiy the missing particle in the following nuclear equation. Please help!How do i DO THIS? **Identify the Missing Particle in the Following Nuclear Equation:**\[ \text{^{238}_{92}U} \rightarrow \, ? \, + \, \text{^{4}_{2}He} \, + \, 2 \, \text{^{0}_{0}\gamma} \]**Options:**- \(\text{^{238}_{90}Th}\)- \(\text{^{232}_{88}Ra}\)- \(\text{^{242}_{94}Pu}\)- \(\text{^{234}_{90}Th}\)- \(\text{^{242}_{88}Ra}\)In this problem, we are asked to identify the missing particle in the nuclear reaction where uranium-238 undergoes transformation. A uranium-238 nucleus (with 92 protons and 146 neutrons) transforms into an unknown particle, releasing a helium nucleus (alpha particle) and two gamma rays in the process. Use the principles of conservation of atomic number and mass number to solve for the missing particle.

We have given that Identiy the missing particle in the following nuclear equation. 23892U -------> ? + 42He + 2 00γ We have given 23892U undergo one alpha decay and 2 gamma decay. 23892U -------> abX + 42He + 2 00γ We know that Representation of element is : AZE A is Mass number of element Z is Atomic number of element 23892U have Mass number 238 and Atomic number 92 238 = a + 4 + 0 a = 238 - 4 = 234 92 = b + 2 + 0 b = 92 - 2 = 90 The missing element have mass number 234 and atomic number 90 So that the element is 23490Th 23892U undergo one alpha decay and 2 gamma decay to give 23490Th 23892U -------> 23490Th + 42He + 2 00γ